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CodeForces 597A Divisibility
Time Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64uSubmit Status Practice CodeForces 597ADescriptionFind the number of k-divisible numbers on the segmen原创 2016-08-23 20:32:14 · 322 阅读 · 0 评论 -
CodeForces 598A Tricky Sum
DescriptionIn this problem you are to calculate the sum of all integers from 1 to n, but you should take all powers of two with minus in the sum.For example, for n = 4 the sum is equal to - 1 -原创 2016-08-23 20:24:00 · 309 阅读 · 0 评论 -
LightOJ 1043 Triangle Partitioning
1043 - Triangle Partitioning PDF (English)StatisticsForumTime Limit: 0.5 second(s)Memory Limit: 32 MBSee the picture below.You are given AB, AC原创 2016-08-23 20:40:27 · 350 阅读 · 0 评论 -
LightOJ 1294 Positive Negative Sign
1294 - Positive Negative Sign PDF (English)StatisticsForumTime Limit: 2 second(s)Memory Limit: 32 MBGiven two integers: n and m and n is divisible by原创 2016-08-23 20:50:07 · 469 阅读 · 0 评论 -
LightOJ 1008 Fibsieve`s Fantabulous Birthday
1008 - Fibsieve`s Fantabulous Birthday PDF (English)StatisticsForumTime Limit: 0.5 second(s)Memory Limit: 32 MBFibsieve had a fantabulous (yes, it's a原创 2016-08-23 21:29:32 · 284 阅读 · 0 评论 -
LightOJ 1045 Digits of Factorial
1045 - Digits of Factorial PDF (English)StatisticsForumTime Limit: 2 second(s)Memory Limit: 32 MBFactorial of an integer is defined by the following f原创 2016-08-24 09:33:33 · 243 阅读 · 0 评论 -
LightOJ 1138 Trailing Zeroes
1138 - Trailing Zeroes (III) PDF (English)StatisticsForumTime Limit: 2 second(s)Memory Limit: 32 MBYou task is to find minimal natural number N, so th原创 2016-08-24 10:12:24 · 363 阅读 · 0 评论 -
LightOJ 1182 Parity
1182 - Parity PDF (English)StatisticsForumTime Limit: 0.5 second(s)Memory Limit: 32 MBGiven an integer n, first we represent it in binary. Then we cou原创 2016-08-25 17:54:36 · 318 阅读 · 0 评论 -
LightOJ 1225 Palindromic Numbers
1225 - Palindromic Numbers (II) PDF (English)StatisticsForumTime Limit: 0.5 second(s)Memory Limit: 32 MBA palindromic number or numeral palindrome is原创 2016-08-25 17:57:54 · 314 阅读 · 0 评论