调用python函数的不同方法效率对比测试

方法1:

用注册DuckDB自定义函数的方法, 我用的是1.3.2版的DuckDB, 在create_function时总是报错,

  File "C:\d\pyduck.txt", line 32, in <module>
    duckdb.create_function("count_composition_ways_optimized", count_composition_ways_optimized, [VARCHAR, [VARCHAR]], BIGINT)
    ~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
RuntimeError: Unable to cast Python instance of type <class 'list'> to C++ type '?' (#define PYBIND11_DETAILED_ERROR_MESSAGES or compile in debug mode for details)

后来看到文档,
Type Annotation
When the function has type annotation it’s often possible to leave out all of the optional parameters. Using DuckDBPyType we can implicitly convert many known types to DuckDBs type system.

不指定类型,反而好了。

def count_composition_ways_optimized(a: str, b: set) -> int:
    """
    优化版本:限制子串最大长度,提高效率
    """
    n = len(a)
    if n == 0:
        return 1
    
    # 计算集合中字符串的最大长度
    max_len = max(len(word) for word in b) if b else 0
    
    dp = [0] * (n + 1)
    dp[0] = 1
    
    for i in range(1, n + 1):
        # 只检查可能的子串长度,避免不必要的检查
        for length in range(1, min(i, max_len) + 1):
            start = i - length
            if a[start:i] in b:
                dp[i] += dp[start]
            #print(i, length,start,dp)
        #print(i, dp)
    return dp[n]

a,b='bill', ['bi', 'l','ike']

print(count_composition_ways_optimized(a, b))

import duckdb
from duckdb.typing import VARCHAR, BIGINT
from duckdb import list_type, struct_type
duckdb.create_function("count_composition_ways_optimized", count_composition_ways_optimized)  #, [VARCHAR, [[VARCHAR]], BIGINT)
s="""
with recursive co as(
select trim(unnest(string_split(c, ',')))c from (from read_csv('2419-input.txt', header=0, delim='-')t(c) limit 1)), 
c2 as(select list(c) c from co), 
w as(select w from read_csv('2419-input.txt', header=0, delim='-', skip=2) t(w))
select sum(count_composition_ways_optimized(w, c)) sum_of_way from c2,w 
-- select w, count_composition_ways_optimized(w, c) sum_of_way from c2,w limit 3
"""
import time
t=time.time();print(duckdb.sql(s), time.time()-t)

上述程序的运行结果

C:\d>python pyduck.txt
1
┌─────────────────┐
│   sum_of_way    │
│     int128      │
├─────────────────┤
│ 950763269786650 │
└─────────────────┘
 0.0038411617279052734

方法2:
用手工方法把数据拆成a、b两部分,a部分是待拆解字符串,用csv模块读取一行,b是子字符串列表。

import sys
import time
import csv
with open('2419-input.txt', mode='r') as file:
    csvFile = csv.reader(file)
    for lines in csvFile:
        b=[i.strip() for i in lines]
        #print(lines)
        break

def count_composition_ways_optimized(a: str, b: set) -> int:
    """
    优化版本:限制子串最大长度,提高效率
    """
    n = len(a)
    if n == 0:
        return 1
    
    # 计算集合中字符串的最大长度
    max_len = max(len(word) for word in b) if b else 0
    
    dp = [0] * (n + 1)
    dp[0] = 1
    
    for i in range(1, n + 1):
        # 只检查可能的子串长度,避免不必要的检查
        for length in range(1, min(i, max_len) + 1):
            start = i - length
            if a[start:i] in b:
                dp[i] += dp[start]
    
    return dp[n]

def main():
    if len(sys.argv) != 2:
        print("用法: python script.py <文件名>")
        return
    t = time.time()
    filename = sys.argv[1]
    cnt=0
    try:
        with open(filename, 'r', encoding='utf-8') as file:
            while True:
                line = file.readline().strip()
                if line == '':
                    break
                
                cnt+=count_composition_ways_optimized(line, b)

    except FileNotFoundError:
        print(f"错误: 文件 '{filename}' 不存在")
    except Exception as e:
        print(f"错误: {e}")
    print(cnt)
    print(f"耗时: {round(time.time()-t, 4)} s")


if __name__ == "__main__":
    main()

执行结果是

950763269786650
耗时: 0.3117 s

算得的结果相同,反而是DuckDB调用python函数更快,估计一与DuckDB并行计算有关, 二是Python确实慢。同样的程序用pypy执行,就是下面的结果

950763269786650
鑰楁椂: 0.0885 s

补记:
我搞错了,方法1不该把计时输出放在同一个print里,这样就正常了

t=time.time();print(duckdb.sql(s));print(time.time()-t)
0.6274137496948242
评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
红包 添加红包
表情包 插入表情
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值