一个简单的多线程例子-互斥量_互斥解决多线程冲突简单案例-优快云博客

本文介绍了一个使用C++实现的简单线程同步示例。通过创建两个线程并利用互斥量来控制对共享资源（票数）的访问，确保了线程安全。其中一个线程处理较慢的操作，而另一个线程则几乎立即尝试获取下一个票数。

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// Mutex.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <windows.h>
#include <iostream>

using namespace std;

DWORD WINAPI Func1Proc(LPVOID lpParam);
DWORD WINAPI Func2Proc(LPVOID lpParam);

static int tickets = 100;
HANDLE m_hMutex;

int _tmain(int argc, _TCHAR* argv[])
{
	HANDLE hThread1;
	HANDLE hThread2;

	hThread1 = CreateThread(NULL, 0, Func1Proc, NULL, 0, NULL);
	hThread2 = CreateThread(NULL, 0, Func2Proc, NULL, 0, NULL);

	CloseHandle(hThread1);
	CloseHandle(hThread2);

	m_hMutex = CreateMutex(NULL, FALSE, L"tickets"); // 如果为TRUE，则此互斥量被主线程占用，需要调用 ReleaseMutex(m_hMutex);

	getchar();

	CloseHandle(m_hMutex);

	return 0;
}

DWORD WINAPI Func1Proc(LPVOID lpParameter)
{
	while (TRUE)
	{
		WaitForSingleObject(m_hMutex, INFINITE);

		if (tickets > 0)
		{
			Sleep(300);
			cout<<"Thread1 sell tickets:"<<tickets--<<endl;
		}
		else 
		{
			break;
		}

		ReleaseMutex(m_hMutex);
	}

	return 0;
}

DWORD WINAPI Func2Proc(LPVOID lpParameter)
{
	while (TRUE)
	{
		WaitForSingleObject(m_hMutex, INFINITE);

		if (tickets > 0)
		{
			Sleep(1);
			cout<<"Thread2 sell tickets:"<<tickets--<<endl;
		}
		else 
		{
			break;
		}

		ReleaseMutex(m_hMutex);
	}

	return 0;
}