java xstream中的xml转对象时解析有属性和值的问题

最新推荐文章于 2021-02-03 13:42:40 发布

kofandlizi

最新推荐文章于 2021-02-03 13:42:40 发布

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分类专栏： JAVA 文章标签： java xml search class integer object

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<search ver="3.0">
    <loc id="ARBA0009" type="1">Buenos Aires, Argentina</loc>
    <loc id="BRXX1283" type="1">Buenos Aires, Brazil</loc>
    <loc id="ARDF0127" type="1">Aeroparque Buenos Aires, Argentina</loc>
    <loc id="MXJO0669" type="1">Concepcion De Buenos Aires, Mexico</loc>
    <loc id="MXPA1785" type="1">San Nicolas De Buenos Aires, Mexico</loc>
    <loc id="ARBA0005" type="1">Balcarce, Argentina</loc>
    <loc id="ARBA0008" type="1">Bragado, Argentina</loc>
    <loc id="ARBA0010" type="1">Campana, Argentina</loc>
    <loc id="ARBA0016" type="1">Chascomus, Argentina</loc>
    <loc id="ARBA0019" type="1">Chivilcoy, Argentina</loc>
</search>

public class City {

    private String  id;
    private Integer type;
    private String  name;

    // getters & setters...
}
写个转换器
public class CityConverter implements Converter {

    public void marshal(Object value, HierarchicalStreamWriter writer, MarshallingContext context) {
        City city = (City) value;
        writer.addAttribute("id", city.getId());
        writer.addAttribute("type", city.getType().toString());
        writer.setValue(city.getName());
    }

    public Object unmarshal(HierarchicalStreamReader reader, UnmarshallingContext context) {
        City city = new City();
        city.setName(reader.getValue());
        city.setId(reader.getAttribute("id"));
        city.setType(reader.getAttribute("type"));
        return city;
    }

    public boolean canConvert(Class clazz) {
        return clazz.equals(City.class);
    }

}
注册转换器
xStream.registerConverter(new CityConverter());
xStream.alias("search", List.class);
xStream.alias("loc", City.class);