HM之基于哈达玛变换的SATD计算

HEVC_jdf

于 2016-10-08 19:26:30 发布

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本文链接：https://blog.youkuaiyun.com/king20168/article/details/52759843

本文详细探讨了哈达玛变换在HM（Harmonyos Middleware）框架下如何应用于SATD（Self-Admitted Technical Debt）的计算。通过利用哈达玛变换的特性，实现了对软件质量欠债的有效量化和分析，为软件维护和优化提供了科学依据。

// 函数功能是计算8×8块的哈达玛变换，并计算其SAD值，m2[8][8]存放最终的变换结果

Int xCalcHADs8x8_ISlice(Pel *piOrg, Int iStrideOrg)
{
Int k, i, j, jj;
Int diff[64], m1[8][8], m2[8][8], m3[8][8], iSumHad = 0;

//把8×8块像素存放在一维数组中
for( k = 0; k < 64; k += 8 )
{
diff[k+0] = piOrg[0] ;
diff[k+1] = piOrg[1] ;
diff[k+2] = piOrg[2] ;
diff[k+3] = piOrg[3] ;
diff[k+4] = piOrg[4] ;
diff[k+5] = piOrg[5] ;
diff[k+6] = piOrg[6] ;
diff[k+7] = piOrg[7] ;

piOrg += iStrideOrg; //指针指向下一行
}

//horizontal 水平变换，计算V=X×H，
for (j=0; j < 8; j++)
{
jj = j << 3; //一次算8个，乘8换行
m2[j][0] = diff[jj ] + diff[jj+4];
m2[j][1] = diff[jj+1] + diff[jj+5];
m2[j][2] = diff[jj+2] + diff[jj+6];
m2[j][3] = diff[jj+3] + diff[jj+7];
m2[j][4] = diff[jj ] - diff[jj+4];
m2[j][5] = diff[jj+1] - diff[jj+5];
m2[j][6] = diff[jj+2] - diff[jj+6];
m2[j][7] = diff[jj+3] - diff[jj+7];

m1[j][0] = m2[j][0] + m2[j][2