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最新推荐文章于 2018-08-19 23:03:40 发布

原创最新推荐文章于 2018-08-19 23:03:40 发布 · 696 阅读

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本文介绍了一个简单的编程问题，要求根据给定的答案构造最简单的数学方程。输入为一个符号及其对应的值，输出则是构建出的最简单方程。示例中展示了如何直接将输入作为输出返回，提供了一种解决问题的方法。

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Description

Some acm problem is hard to read but easy to solve, sometimes you could have a try even you can't understand it.This problem is a good example for this ^^

Celebrity jeopardy

It's hard to construct a problem that's so easy that everyone will get it, yet still difficult enough to be worthy of some respect. Usually, we err on one side or the other. How simple can a problem really be?

Here, as in Celebrity Jepoardy, questions and answers are a bit confused, and, because the participants are elebrities, there’s a real need to make the challenges simple. Your program needs to prepare a question to be solved --- an equation to be solved --- given the answer. Specifically, you have to write a program which finds the simplest possible equation to be solved given the answer, considering all possible equations using the standard mathematical symbols in the usual manner. In this context, simplest can be defined unambiguously several different ways leading to the same path of resolution. For now, find the equation whose transformation into the desired answer requires the least effort.

For example, given the answer X = 2, you might create the equation 9 - X = 7. Alternately, you could build the system X > 0; X^2 = 4. These may not be the simplest possible equations. Solving these mind-scratchers might be hard for a celebrity.

Input

Each input line contains a solution in the form <symbol> = <value>

Output

For each input line, print the simplest system of equations which would to lead to the provided solution, respecting the use of space exactly as in the input.

Sample Input

Y = 3
X=9

Sample Output

Y = 3
X=9

KEY:有种被耍的感觉……

  

 

Source:#include<iostream>
using namespace std;

int main()
...{
    char s[50];
    while(gets(s))
    ...{
        cout<<s<<endl;
    }
}