fjnu 1703 Keep on Truckin'

在一场紧迫的任务中,Boudreaux与Thibodeaux必须连夜运送一批货物到巴吞鲁日。故事通过一系列的对话展现了他们是否能够成功通过三个不同高度的地下通道的情景。

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Description

Boudreaux and Thibodeaux are on the road again . . .
"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"
"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit
through all of them, so just keep that motor running!"
"We're not going to make it, I say!"
So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound
of his own wheels drive him crazy?

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the
following description.
The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number
represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusiv

Output

There will be exactly one line of output. This line will be:
NO CRASH
if the height of the 18-wheeler is less than the height of each of the underpasses, or:
CRASH X
otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go
under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

Sample Input

180 160 170

 

Sample Output

CRASH 160

 

KEY:很简单,就是和168比较;-_-还不如考英语;

 

Source:

#include
<iostream>
using namespace std;

int a[4];

void fun()
{
        
for(int i=1;i<=3;i++)
        
{
            
if(a[i]<=168)
            
{
                cout
<<"CRASH "<<a[i]<<endl;
                
return ;
            }

        }

        cout
<<"NO CRASH"<<endl;
    
}


int main()
{
    
while(cin>>a[1]>>a[2]>>a[3])
    
{
        fun();
    }

        
return 0;
}

 
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