8421BCD码字节数组:
用4位二进制数来表示1位十进制数(只能是0~9这10个数码),是一种二进制的数字编码形式。利用了四个位元来储存一个十进制的数码,使二进制和十进制之间的转换得以快捷的进行。
BCD字节数组转为字符串:
/**
* BCD字节数组转为字符串
* @param bytes
* @return
*/
public static String bcd2String(byte[] bytes) {
StringBuilder temp = new StringBuilder(bytes.length * 2);
for (int i = 0; i < bytes.length; i++) {
// 高四位
temp.append((bytes[i] & 0xf0) >>> 4);
// 低四位
temp.append(bytes[i] & 0x0f);
}
return temp.toString().substring(0, 1).equalsIgnoreCase("0") ? temp.toString().substring(1) : temp.toString();
}
BCD转char[]:
//仅支持0~9这10个数码
/** BCD转String */
public static String toString(byte[] bcd) {
return new String(toChars(bcd));
}
/** BCD转char[] */
public static char[] toChars(byte[] bcd) {
char[] chars = new char[bcd.length * 2];
for (int i = 0, j = 0; i < bcd.length; i++) {
chars[j++] = (char) (48 + (bcd[i] >> 4 & 0xf));
chars[j++] = (char) (48 + (bcd[i] & 0xf));
}
return chars;
}
字符串转为BCD字节数组:
/**
* 字符串转为BCD字节数组
* @param str
* @return BCD字节数组
*/
public static byte[] stringBcd(String str) {
//若为奇数,补0为偶
if ((str.length() & 0x1) == 1) {
str = "0" + str;
}
byte ret[] = new byte[str.length() / 2];
byte bs[] = str.getBytes();
for (int i = 0; i < ret.length; i++) {
byte high = ascII2Bcd(bs[2 * i]);
byte low = ascII2Bcd(bs[2 * i + 1]);
ret[i] = (byte) ((high << 4) | low);
}
return ret;
}
public static byte ascII2Bcd(byte asc) {
if ((asc >= '0') && (asc <= '9'))
return (byte) (asc - '0');
else if ((asc >= 'A') && (asc <= 'F'))
return (byte) (asc - 'A' + 10);
else if ((asc >= 'a') && (asc <= 'f'))
return (byte) (asc - 'a' + 10);
else
return (byte) (asc - 48);
}