题目描述已经给出了解法:中序遍历(左根右),如果要就地更新原树其实还是有些麻烦的,但如果中序遍历后新建一个数就很简单了。
/**
* Definition for a binary tree node.
* public class TreeNode {
* public int val;
* public TreeNode left;
* public TreeNode right;
* public TreeNode(int x) { val = x; }
* }
*/
public class Solution {
List<int> list = new List<int>();
public TreeNode IncreasingBST(TreeNode root) {
if(root == null)
return root;
func(root);
TreeNode ts = new TreeNode(0);
TreeNode t = new TreeNode(list[0]);
ts.right = t;
for(int i = 1;i < list.Count(); i++)
{
t.right = new TreeNode(list[i]);
t = t.right;
}
return ts.right;
}
public void func(TreeNode t)
{
if(t == null)
return;
func(t.left);
list.Add(t.val);
func(t.right);
}
}