虚函数参数的默认值

#include <iostream>
#include <complex>
using namespace std;

class Base
{
public:
 virtual void f(int);
 virtual void f(double);
 virtual void g(int i = 10);
};

void Base::f(int)
{
 cout << "Base::f(int)" << endl;
}

void Base::f(double)
{
 cout <<  "Base::f(double)" << endl;
}

void Base::g(int i)
{
    cout << i << endl;
}

class Derived : public Base
{
 
public :
 void f(complex<double>);
 void g(int i = 20);
 // using Base::f;
};

void Derived::f(complex<double>)
{
 cout << "Derived::f(complex<double>)" << endl;
}

void Derived::g(int i)
{
 cout << "Derived::g(int i)" << i << endl;
}

int  main(int argc, char* argv[])
{
   Base * pb = new Derived;
  pb->g();
 delete pb;
 return 0;
}

将会输出什么么？

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哈哈　－｜　Derived::g(int i)　１０　（not 20!!）

因为预先设定的参数是有静态型别来设定的，而调用的函数型别则是动态的确定。