static final double x_pi = 3.14159265358979324 * 3000.0 / 180.0;
public static class Pos {
public double lat;
public double lon;
}
public static Pos bd_encrypt(Pos pos) {
Pos result = new Pos();
double x = pos.lon, y = pos.lat;
double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);
double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);
result.lon = z * Math.cos(theta) + 0.0065;
result.lat = z * Math.sin(theta) + 0.006;
return result;
}火星坐标转换成百度坐标
BD坐标加密算法解析
最新推荐文章于 2024-01-24 11:31:36 发布
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