随机密码生成。编写程序，在26个字母大小写和9个数字组成的列表中随机生成10个8位密码。

Silence战

于 2019-08-02 12:51:28 发布

阅读量6.9w

点赞数 47

CC 4.0 BY-SA版权

分类专栏： Python语言程序设计（第二版）练习题文章标签： python 编程 python语言程序设计嵩天

本文链接：https://blog.youkuaiyun.com/jwsgd/article/details/98191210

Python语言程序设计（第二版）练习题专栏收录该内容

4 篇文章

订阅专栏

本文介绍了一种使用Python的random模块生成随机密码的方法。通过定义包含大小写字母和数字的字符集，利用random.choice和random.sample函数，实现了在指定范围内生成8位长度的密码，并重复此过程10次以生成多个密码。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

#e6.1随机密码生成，在26个字母大小写和9个数字组成的列表中随机生成10个8位密码
import random
s = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z",
     "A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z",
     "0","1","2","3","4","5","6","7","8","9"] #根据要求定义列表元素范围，无要求时也可定义字符串更方便


#方法1：
for i in range(10):   #循环10遍，生成10组密码
    for i in range(8):
        print (random.choice(s),end="")  #random.choice(seq)实现从序列或集合seq中随机选取一个元素
    print("\n")   #每输出一组后，换行输出下一组

    

#方法2：
for i in range(10): 	#循环10遍，生成10组密码 
    k = random.sample(s,8)  #random.sample(seq, k)实现从序列或集合seq中随机选取k个独立的的元素,以列表形式输出
    for i in k:		#遍历随机数组中的每一项并输出
        print(i,end="")
    print("\n")	    #每输出一组后，换行输出下一组