Problem Statement
(Source) Given an unsorted array nums
, reorder it such that nums[0] < nums[1] > nums[2] < nums[3]...
.
Example:
(1) Given nums = [1, 5, 1, 1, 6, 4]
, one possible answer is [1, 4, 1, 5, 1, 6]
.
(2) Given nums = [1, 3, 2, 2, 3, 1]
, one possible answer is [2, 3, 1, 3, 1, 2]
.
Note:
You may assume all input has valid answer.
Follow Up:
Can you do it in O(n) time and/or in-place with O(1) extra space?
Tags: Sort
.
Solution 1 - Sort
O(nlogn) time complexity though :)
class Solution(object):
def wiggleSort(self, nums):
"""
:type nums: List[int]
:rtype: void Do not return anything, modify nums in-place instead.
"""
nums.sort()
half = len(nums[::2])
nums[::2], nums[1::2] = nums[:half][::-1], nums[half:][::-1]
Solution 2
TODO