代码如下:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
Date d1 = df.parse("2006-05-26 12:00:00");
Date d2 = df.parse("2006-07-02 11:20:00");
long diff = d1.getTime() - d2.getTime();//这样得到的差值是微秒级别
long days = diff / (1000 * 60 * 60 * 24);
long hours = (diff-days*(1000 * 60 * 60 * 24))/(1000* 60 * 60);
long minutes = (diff-days*(1000 * 60 * 60 * 24)-hours*(1000* 60 * 60))/(1000* 60);
System.out.println(""+days+"天"+hours+"小时"+minutes+"分");
}
catch (Exception e)
{
}
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
Date d1 = df.parse("2006-05-26 12:00:00");
Date d2 = df.parse("2006-07-02 11:20:00");
long diff = d1.getTime() - d2.getTime();//这样得到的差值是微秒级别
long days = diff / (1000 * 60 * 60 * 24);
long hours = (diff-days*(1000 * 60 * 60 * 24))/(1000* 60 * 60);
long minutes = (diff-days*(1000 * 60 * 60 * 24)-hours*(1000* 60 * 60))/(1000* 60);
System.out.println(""+days+"天"+hours+"小时"+minutes+"分");
}
catch (Exception e)
{
}
本文介绍了一段Java代码,该代码使用SimpleDateFormat类解析两个指定的日期时间字符串,并计算它们之间的差值,最终以天数、小时数和分钟数的形式展示结果。
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