Questions for C++

本文精选了C++面试中常见的技术问题,并提供了详细的解答。覆盖了从基本概念到高级特性,如重载与覆写区别、多态实现、字符串复制函数编写、数据结构特性比较等,帮助读者深入理解C++编程语言。

Questions for C++

Name:

Position:

Phone Number:

Time: 2 hours

1. What is overload? What is override? Can we overload functions by various kinds of return values? Why? (5)

a.

overload means there are several functions which have the same name in the same class, the function called operation is determined by the parameters number

override means use the same function name, parameter and return value to override the method of parent class in derived class

b.

No

c.

Overload function called is determined by the parameters, has not the relation to return value. So we can’t differ the overload functions by various kinds of return values

2. What is polymorphism in C++? You could draw a picture to depict your understand. (5)

Polymorphism points to the methods that override the parent class’s method with the same name, parameter and return value.

class CPerson

{

public:

void virtual AboutMe()

{

printf("I am CPerson");

}

}

class CMan : public CPerson

{

public:

void virtual AboutMe()

{

printf("I am CNan");

}

}

class CWoman : public CPerson

{

public:

void virtual AboutMe()

{

printf("I am CWoman");

}

}

void main()

{

CPerson * p = new CPerson();

p->AboutMe(); //I am CPerson

p = new CMan();

p->AboutMe(); //I am CNan

p = new CWoman();

p->AboutMe(); //I am CWoman

}

3. Write function “strcpy” without C++/C string library.(7)

char * strcpy(const char * pSrc, char * pDes)

{

assert(pSrc != NULL && pDes != NULL);

char * pTmp = pDes;

while((*pTmp++ = *pSrc++) != '/0');

return pTmp;

}

4. Describe the following data structures; arrays, linked lists, hash tables and binary trees. How are they different? What are the strengths and weaknesses of each? Give an example of a situation you would use each. (8)

Array is continued block in memory, it can only store the same type data and it’s size is determined while compiling.

Hash table can realize the map between key and value, It also requires a continued memory area when stores data. But it’s data locating utilizes hash code. Good hash code generated algorithm can make the memory utilized ratio very high.

Binary tree is a kind of data structure like tree figure. It can not be continual and it’s size is dynamic. We can realize data sort while utilizing it to store data; it’s time complexity is too low while we search, edit it.

5. Does C++ come with in-built threading support? If yes, how to do that? If no, how can you implement threading support in C++? Please write code piece if needed. (6)

No, C++ does not come with in-built threading support.

6. What is the result of the following program?(7)

#include <iostream.h>
class A
{
public:
A(){cout<<"A::A() called./n";}
virtual ~A(){cout<<"A::~A() called./n";}
};

class B:public A
{
public:
B(int i){
cout<<"B::B() called./n";
buf=new char[i];}
virtual ~B()
{
delete []buf;
cout<<"B::~B() called./n";
}
private:
char *buf;
};

void fun(A *a)
{
delete a;
}

void main()
{
A *a=new B(15);
fun(a);
}

直接执行得到输出结果。

7. What errors are caught at compile time vs link time? Please give at least 2 examples for each situation. (7)

8. The following codes are for 32 bits computers. Please calculate the value of sizeof. (8)

char str[] = "Hello" ;

char *p = str ;

int n = 10;

sizeof(str) = __6________

sizeof(p) = ___4_______

sizeof(n) = ____4______

void Func ( char str[100])

{

sizeof(str) = __4________

}

9. Implement Singleton design pattern with C++.(8)

class CSingleton

{

private:

CSingleton * instance;

CSingleton()

{

instance = NULL;

}

public:

CSingleton * getInstance()

{

if(instance == NULL)

instance = new CSingleton();

return instance;

}

}

10. Please analyze codes and tell what will be the results after running and why. (8)

Code 1:

void GetMemory(char *p)

{

p = (char *)malloc(100);

}

void Test(void)

{

char *str = NULL;

GetMemory(str);

strcpy(str, "hello world");

printf(str);

}

Answer 1:

程序会crash。因为GetMemory()并不能传递动态的内存,Test中的str一直都是NULL,strcpy(str, "hello world")这句将将使程序crash。

Code 2:

char *GetMemory(void)

{

char p[] = "hello world";

return p;

}

void Test(void)

{

char *str = NULL;

str = GetMemory();

printf(str);

}

Answer 2:

程序返回的结果可能是乱码。因为GetMemory()返回的是指向栈内存的指针,该指针的内容不是NULL,但其原先的内容已经被清除,新内容不可知。

11. Is it possible to keep 2 stacks in a single array, if one grows from position one of the array, and the other grows from the last position. Write a procedure PUSH(x, s) that pushes element x onto stack S, where S is one or the other of these two stacks. Include all necessary error checks (15)

12. class String

{

public:

String(const char *str = NULL); // constructor

String(const String &other); // copy constructor

~ String(void); // destructor

String & operate =(const String &other);

private:

char *m_data; // save the string

};

Please write the above four functions. (16)

a.

String::~String(void)

{

delete[] m_data;

}

b.

String::String(const char *str = NULL)

{

if(str == NULL)

{

m_data = new char[1];

m_data[0] = '/0';

}

else

{

m_data = new char[strlen(str) + 1];

strcpy(m_data, str);

}

}

c.

String::String(const String &other)

{

m_data = new char[strlen(other.m_data)+1];

strcpy(m_data, other.m_data);

}

d.

String & String::operate =(const String &other)

{

if(other == &otherL)

return *this;

delete[] m_data;

m_data = new char[strlen(other.m_data)+1];

strcpy(m_data, other.m_data);

return *this;

}

本 PPT 介绍了制药厂房中供配电系统的总体概念与设计要点,内容包括: 洁净厂房的特点及其对供配电系统的特殊要求; 供配电设计的一般原则与依据的国家/行业标准; 从上级电网到工厂变电所、终端配电的总体结构与模块化设计思路; 供配电范围:动力配电、照明、通讯、接地、防雷与消防等; 动力配电中电压等级、接地系统形式(如 TN-S)、负荷等级与可靠性、UPS 配置等; 照明的电源方式、光源选择、安装方式、应急与备用照明要求; 通讯系统、监控系统在生产管理与消防中的作用; 接地与等电位连接、防雷等级与防雷措施; 消防设施及其专用供电(消防泵、排烟风机、消防控制室、应急照明等); 常见高压柜、动力柜、照明箱等配电设备案例及部分设计图纸示意; 公司已完成的典型项目案例。 1. 工程背景与总体框架 所属领域:制药厂房工程的公用工程系统,其中本 PPT 聚焦于供配电系统。 放在整个公用工程中的位置:与给排水、纯化水/注射用水、气体与热力、暖通空调、自动化控制等系统并列。 2. Part 01 供配电概述 2.1 洁净厂房的特点 空间密闭,结构复杂、走向曲折; 单相设备、仪器种类多,工艺设备昂贵、精密; 装修材料与工艺材料种类多,对尘埃、静电等更敏感。 这些特点决定了:供配电系统要安全可靠、减少积尘、便于清洁和维护。 2.2 供配电总则 供配电设计应满足: 可靠、经济、适用; 保障人身与财产安全; 便于安装与维护; 采用技术先进的设备与方案。 2.3 设计依据与规范 引用了大量俄语标准(ГОСТ、СНиП、SanPiN 等)以及国家、行业和地方规范,作为设计的法规基础文件,包括: 电气设备、接线、接地、电气安全; 建筑物电气装置、照明标准; 卫生与安全相关规范等。 3. Part 02 供配电总览 从电源系统整体结构进行总览: 上级:地方电网; 工厂变电所(10kV 配电装置、变压
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值