题目
给定一个二叉树,返回它的中序 遍历。
示例:
输入: [1,null,2,3] 1 \ 2 / 3 输出: [1,3,2]
进阶: 递归算法很简单,你可以通过迭代算法完成
代码
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def inorderTraversal(self, root):
"""
:type root: TreeNode
:rtype: List[int]
"""
res = []
if root == None:
return
s = []
cur = root
while (len(s) != 0) | (cur != None):
while cur:
s.append(cur)
cur = cur.left
cur = s.pop()
res.append(cur.val)
cur = cur.right
return res