The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A "legal" input is a real number in [-1000, 1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then N numbers are given in the next line, separated by one space.
Output Specification:
For each illegal input number, print in a line "ERROR: X is not a legal number" where X is the input. Then finally print in a line the result: "The average of K numbers is Y" where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output "Undefined" instead of Y. In case K is only 1, output "The average of 1 number is Y" instead.
Sample Input 1:7 5 -3.2 aaa 9999 2.3.4 7.123 2.35Sample Output 1:
ERROR: aaa is not a legal number ERROR: 9999 is not a legal number ERROR: 2.3.4 is not a legal number ERROR: 7.123 is not a legal number The average of 3 numbers is 1.38Sample Input 2:
2 aaa -9999Sample Output 2:
ERROR: aaa is not a legal number ERROR: -9999 is not a legal number The average of 0 numbers is Undefined
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<string>
#include<iostream>
const int Max = 1000;
using namespace std;
int n;
string S[Max];
double num[Max];
int ins=0;
bool IsTrue(string s)
{
if(s[0]=='-')
{
if(s[1]>='0'&&s[1]<='9')
{
int flag=0,k=-1;
for(int i=1;i<s.size();i++)
{
if(!(s[i]>='0'&&s[i]<='9'||s[i]=='.'))
{
return false;
}
if(s[i]=='.')
{
if(flag==0)
{
k=i;//找到.的位置
}
flag++;
}
if(flag>=2)
{
return false;
}
}
if(k==-1)//不是小数
{
double ans=0;
for(int i=1;i<s.size();i++)
{
ans=ans*10+(s[i]-'0');
}
if(ans>1000)
return false;
else
{
num[ins++]=-1*ans;
return true;
}
}
else
{
if(s.size()-k-1>=3)
{
return false;
}
else
{
double ans1=0,ans2=0;
for(int i=1;i<k;i++)
{
ans1=ans1*10+(s[i]-'0');
}
for(int i=k+1;i<s.size();i++)
{
ans2=ans2*10+(s[i]-'0');
}
if(s.size()-k-1==2) ans2=ans2/100;
else ans2=ans2/10;
ans1=ans1+ans2;
num[ins++]=-1*ans1;
return true;
}
}
}
else return false;
}
else //正数
{
if(s[0]>='0'&&s[0]<='9')
{
int flag=0,k=-1;
for(int i=0;i<s.size();i++)
{
if(!(s[i]>='0'&&s[i]<='9'||s[i]=='.'))
{
return false;
}
if(s[i]=='.')
{
if(flag==0)
{
k=i;//找到.的位置
}
flag++;
}
if(flag>=2)
{
return false;
}
}
if(k==-1)//不是小数
{
double ans=0;
for(int i=0;i<s.size();i++)
{
ans=ans*10+(s[i]-'0');
}
if(ans>1000)
return false;
else
{
num[ins++]=ans;
return true;
}
}
else
{
if(s.size()-k-1>=3)
{
return false;
}
else
{
double ans1=0,ans2=0;
for(int i=0;i<k;i++)
{
ans1=ans1*10+(s[i]-'0');
}
for(int i=k+1;i<s.size();i++)
{
ans2=ans2*10+(s[i]-'0');
}
if(s.size()-k-1==2) ans2=ans2/100;
else ans2=ans2/10;
ans1=ans1+ans2;
num[ins++]=ans1;
return true;
}
}
}
else return false;
}
}
int main()
{
scanf("%d",&n);
for(int i=0;i<n;i++)
{
getchar();
cin>>S[i];
}
int temp=0;
for(int i=0;i<n;i++)
{
if(IsTrue(S[i])==false)
{
cout<<"ERROR: "<<S[i]<<" is not a legal number"<<endl;
}
}
if(ins==0)
{
cout<<"The average of 0 numbers is Undefined"<<endl;
}
else
{
double mm=0;
for(int i=0;i<ins;i++)
{
mm+=num[i];
//cout<<num[i]<<endl;
}
mm=mm/ins;
if(ins!=1)
printf("The average of %d numbers is %.2f",ins,mm);
else printf("The average of %d number is %.2f",ins,mm);
}
system("pause");
return 0;
}