Stripies
Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 5363 | Accepted: 2746 |
Description
Our
chemical biologists have invented a new very useful form of life called
stripies (in fact, they were first called in Russian - polosatiki, but
the scientists had to invent an English name to apply for an
international patent). The stripies are transparent amorphous amebiform
creatures that live in flat colonies in a jelly-like nutrient medium.
Most of the time the stripies are moving. When two of them collide a
new stripie appears instead of them. Long observations made by our
scientists enabled them to establish that the weight of the new stripie
isn't equal to the sum of weights of two disappeared stripies that
collided; nevertheless, they soon learned that when two stripies of
weights m1 and m2 collide the weight of resulting stripie equals to
2*sqrt(m1*m2). Our chemical biologists are very anxious to know to what
limits can decrease the total weight of a given colony of stripies.
You are to write a program that will help them to answer this question. You may assume that 3 or more stipies never collide together.
You are to write a program that will help them to answer this question. You may assume that 3 or more stipies never collide together.
Input
The
first line of the input contains one integer N (1 <= N <= 100) -
the number of stripies in a colony. Each of next N lines contains one
integer ranging from 1 to 10000 - the weight of the corresponding
stripie.
Output
The
output must contain one line with the minimal possible total weight of
colony with the accuracy of three decimal digits after the point.
Sample Input
3 72 30 50
Sample Output
120.000
解题思路的关键在于:
最小的值是从大向小进行计算,可以使用不等式进行证明。
import java.util.*;
import java.text.*;
public class Main {
public static void main(String[] args) {
Scanner cin = new Scanner(System.in);
int num = Integer.valueOf(cin.nextLine()).intValue();
List list = new ArrayList();
for(int i = 0; i < num; i++)
list.add(Double.valueOf(cin.nextLine()));
Collections.sort(list);
double result, temp = 0;
double a, b = 0;
if(list.size() == 1)
result = Double.valueOf((Double)list.get(0)).doubleValue();
else
{
int index = list.size() - 1;
a = Double.valueOf((Double)list.get(index)).doubleValue();
b = Double.valueOf((Double)list.get(index-1)).doubleValue();
result = 2 * Math.sqrt(a * b);
for(int i = index - 2; i>=0; i--)
{
a = Double.valueOf((Double)list.get(i)).doubleValue();
result = 2 * Math.sqrt(a * result);
}
}
DecimalFormat df = new DecimalFormat("#.000");
System.out.println(df.format(result));
}
}