HDU5873

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5873

Football Games

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1204    Accepted Submission(s): 466


Problem Description
A mysterious country will hold a football world championships---Abnormal Cup, attracting football teams and fans from all around the world. This country is so mysterious that none of the information of the games will be open to the public till the end of all the matches. And finally only the score of each team will be announced.
 
  At the first phase of the championships, teams are divided into M groups using the single round robin rule where one and only one game will be played between each pair of teams within each group. The winner of a game scores 2 points, the loser scores 0, when the game is tied both score 1 point. The schedule of these games are unknown, only the scores of each team in each group are available.
 
  When those games finished, some insider revealed that there were some false scores in some groups. This has aroused great concern among the pubic, so the the Association of Credit Management (ACM) asks you to judge which groups' scores must be false.


 

Input
Multiple test cases, process till end of the input.
 
  For each case, the first line contains a positive integers M , which is the number of groups.
  The i -th of the next M lines begins with a positive integer Bi representing the number of teams in the i -th group, followed by Bi nonnegative integers representing the score of each team in this group.


number of test cases <= 10
M<= 100
B[i]<= 20000
score of each team <= 20000


 

Output
For each test case, output M lines. Output ``F" (without quotes) if the scores in the i-th group must be false, output ``T" (without quotes) otherwise. See samples for detail.


 

Sample Input
  
2 3 0 5 1 2 1 1


 

Sample Output
  
F T

题目大意:

求给出的足球队的分数是真是假

 

只需要满足以下4个条件:

1. 总分数等于 n*(n-1),因为每场比赛总能获得两分

2. 最高分数小于 2*(n-1)

3. 奇数分数必须是偶数个

4. 得0分的队伍小于1个

 

我用的score[0]存的总分,但是我之前定义了一个maxn存总分 结果超时了

 

代码:

#include<cstdio>
#include<iostream>
using namespace std;
int score[20020];
int main()
{
    int t ;
    while(scanf("%d", &t) != EOF)
    {
        while(t--)
        {
            int m,sum1,sum2,maxt=-1;
            sum1 = 0;
            sum2 = 0;
            score[0]=0;
            scanf("%d", &m);
            for(int i = 1; i<= m; i++)
            {
                scanf("%d", &score[i]);
                score[0] += score[i];
                if(score[i]%2 != 0)
                  sum1++;
                if(score[i] == 0)
                  sum2++;
                if(score[i]>maxt)
                 maxt=score[i];
            }
            if(maxt > 2*(m-1))
            {
                printf("F\n");
                continue;
            }
            if(score[0] != m*(m-1))
            {
                printf("F\n");
                continue;
            }
            if(sum1%2!=0)
            {
                printf("F\n");
                continue;
            }
            if(sum2>1)
            {
                printf("F\n");
                continue;
            }
            printf("T\n");
        }
    }
    return 0;
}


 


 

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