HDU2602

题目的链接：http://acm.hdu.edu.cn/showproblem.php?pid=2602

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

 

Output

One integer per line representing the maximum of the total value (this number will be less than 2³¹).

 

Sample Input

   
   

    
    1
5 10
1 2 3 4 5
5 4 3 2 1
   
   

 

Sample Output

   
   

    
    14
   
   

简单的01背包，但是要注意数组的大小和输入的数据，注意 f[0]有价值。

#include<cstdio>
#include<iostream>
#include<cstring>
#include<algorithm>
using namespace std;
int V[1010];
int w[1010];
int f[1010];
int main()
{
    int T;
    scanf("%d",&T);
    while( T--)
    {
        ///memset(V,0,sizeof(V));
        ///memset(w,0,sizeof(w));
        int n,v;
        scanf("%d%d",&n,&v);
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&w[i]);
        }
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&V[i]);
        }
        memset(f,0,sizeof(f));
        for(int i=1;i<=n;i++)
        {
            for(int j=v;j>=V[i];j--)
            {
                f[j]=max(f[j],f[j-V[i]]+w[i]);
            }
        }
        printf("%d\n",f[v]);

    }
    return 0;
}