原题网址:https://leetcode.com/problems/single-number/
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
方法:利用异或运算的特性。
public class Solution {
public int singleNumber(int[] nums) {
int single = 0;
for(int num: nums) single ^= num;
return single;
}
}

本文介绍了一种解决LeetCode中单数元素问题的方法,利用异或运算的特性找到数组中仅出现一次的数字。该算法具有线性时间复杂度且不使用额外内存。
424

被折叠的 条评论
为什么被折叠?



