原题网址:https://leetcode.com/problems/clone-graph/
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use# as a separator for each node, and
, as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
- First node is labeled as
0. Connect node0to both nodes1and2. - Second node is labeled as
1. Connect node1to node2. - Third node is labeled as
2. Connect node2to node2(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
方法:使用哈希映射保存已克隆的节点。
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
private Map<Integer, UndirectedGraphNode> map = new HashMap<>();
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) return null;
UndirectedGraphNode cloned = map.get(node.label);
if (cloned != null) return cloned;
cloned = new UndirectedGraphNode(node.label);
map.put(cloned.label, cloned);
for(UndirectedGraphNode neighbor: node.neighbors) {
cloned.neighbors.add(cloneGraph(neighbor));
}
return cloned;
}
}

本文介绍了一种通过哈希映射实现无向图深拷贝的方法。此方法利用哈希表保存已克隆的节点,确保每个节点仅被复制一次,并正确地建立新图中各节点间的连接。

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