银行家算法

/* 银行家算法,操作系统概念(OS concepts Six Edition)
 作者:ctu_85
*/
#include "malloc.h"
#include "stdio.h"
#define alloclen sizeof(struct allocation)
#define maxlen sizeof(struct max)
#define avalen sizeof(struct available)
#define needlen sizeof(struct need)
#define finilen sizeof(struct finish)
#define pathlen sizeof(struct path)
struct allocation
{
int value;
struct allocation *next;
};
struct max
{
int value;
struct max *next;
};
struct available
{
int value;
struct available *next;
};
struct need
{
int value;
struct need *next;
};
struct path
{
int value;
struct path *next;
};
struct finish
{
int stat;
struct finish *next;
};
int main()
{
int row,colum,status=0,i,j,t,temp,processtest;
struct allocation *allochead,*alloc1,*alloc2,*alloctemp;
struct max *maxhead,*maxium1,*maxium2,*maxtemp;
struct available *avahead,*available1,*available2,*availabletemp,*workhead,*work1,*work2,*worktemp,*worktemp1;
struct need *needhead,*need1,*need2,*needtemp;
struct finish *finihead,*finish1,*finish2,*finishtemp;
struct path *pathhead,*path1,*path2,*pathtemp;
char c;
printf("/nPlease enter the type of sources the system has:/n");
scanf("%d",&colum);
printf("Please enter the number of processes now in the memory:/n");
scanf("%d",&row);
printf("Please enter the allocation array:/n");
for(i=0;i<row;i++)
{
printf("The allocation for process p%d:/n",i);
for (j=0;j<colum;j++)
{
printf("The type %c system resource allocated:/n",'A'+j);
if(status==0)
{
allochead=alloc1=alloc2=(struct allocation*)malloc(alloclen);
alloc1->next=alloc2->next=NULL;
scanf("%d",&allochead->value);
status++;
}
else
{
alloc2=(struct allocation *)malloc(alloclen);
scanf("%d,%d",&alloc2->value);
if(status==1)
{
allochead->next=alloc2;
status++;
}
alloc1->next=alloc2;
alloc1=alloc2;
}
}
}
alloc2->next=NULL;
status=0;
printf("Please enter the max array:/n");
for(i=0;i<row;i++)
{
printf("The max needed from process p%d:/n",i);
for (j=0;j<colum;j++)
{
printf("The type %c maxium system resource may needed:/n",'A'+j);
if(status==0)
{
maxhead=maxium1=maxium2=(struct max*)malloc(maxlen);
maxium1->next=maxium2->next=NULL;
scanf("%d",&maxium1->value);
status++;
}
else
{
maxium2=(struct max *)malloc(maxlen);
scanf("%d,%d",&maxium2->value);
if(status==1)
{
maxhead->next=maxium2;
status++;
}
maxium1->next=maxium2;
maxium1=maxium2;
}
}
}
maxium2->next=NULL;
status=0;
printf("Please enter the available array now exists in the system:/n");
for (j=0;j<colum;j++)
{
printf("The type %c available system resource number:/n",'A'+j);
if(status==0)
{
avahead=available1=available2=(struct available*)malloc(avalen);
workhead=work1=work2=(struct available*)malloc(avalen);
available1->next=available2->next=NULL;
work1->next=work2->next=NULL;
scanf("%d",&available1->value);
work1->value=available1->value;
status++;
}
else
{
available2=(struct available*)malloc(avalen);
work2=(struct available*)malloc(avalen);
scanf("%d,%d",&available2->value);
work2->value=available2->value;
if(status==1)
{
avahead->next=available2;
workhead->next=work2;
status++;
}
available1->next=available2;
available1=available2;
work1->next=work2;
work1=work2;
}
}
available2->next=NULL;
work2->next=NULL;
status=0;
alloctemp=allochead;
maxtemp=maxhead;
for(i=0;i<row;i++)
for (j=0;j<colum;j++)
{
if(status==0)
{
needhead=need1=need2=(struct need*)malloc(needlen);
need1->next=need2->next=NULL;
need1->value=maxtemp->value-alloctemp->value;
status++;
}
else
{
need2=(struct need *)malloc(needlen);
need2->value=(maxtemp->value)-(alloctemp->value);
if(status==1)
{
needhead->next=need2;
status++;
}
need1->next=need2;
need1=need2;
}
maxtemp=maxtemp->next;
alloctemp=alloctemp->next;
}
need2->next=NULL;
status=0;
for(i=0;i<row;i++)
{
if(status==0)
{
finihead=finish1=finish2=(struct finish*)malloc(finilen);
finish1->next=finish2->next=NULL;
finish1->stat=0;
status++;
}
else
{
finish2=(struct finish*)malloc(finilen);
finish2->stat=0;
if(status==1)
{
finihead->next=finish2;
status++;
}
finish1->next=finish2;
finish1=finish2;
}
}
finish2->next=NULL;                     /*Initialization compleated*/
status=0;
processtest=0;
for(temp=0;temp<row;temp++)
{
alloctemp=allochead;
needtemp=needhead;
finishtemp=finihead;
worktemp=workhead;
for(i=0;i<row;i++)
{
worktemp1=worktemp;
if(finishtemp->stat==0)
{
for(j=0;j<colum;j++,needtemp=needtemp->next,worktemp=worktemp->next)
if(needtemp->value<=worktemp->value)
processtest++;
if(processtest==colum)
{
for(j=0;j<colum;j++)
{
worktemp1->value+=alloctemp->value;
worktemp1=worktemp1->next;
alloctemp=alloctemp->next;
}
if(status==0)
{
pathhead=path1=path2=(struct path*)malloc(pathlen);
path1->next=path2->next=NULL;
path1->value=i;
status++;
}
else
{
path2=(struct path*)malloc(pathlen);
path2->value=i;
if(status==1)
{
pathhead->next=path2;
status++;
}
path1->next=path2;
path1=path2;
}
finishtemp->stat=1;
}
else
{
for(t=0;t<colum;t++)
alloctemp=alloctemp->next;
finishtemp->stat=0;
}
}
else
for(t=0;t<colum;t++)
{
needtemp=needtemp->next;
alloctemp=alloctemp->next;
}
processtest=0;
worktemp=workhead;
finishtemp=finishtemp->next;
}
}
path2->next=NULL;
finishtemp=finihead;
for(temp=0;temp<row;temp++)
{
if(finishtemp->value==0)
{
printf("/nWARNING,the system is in nonsafe status!/n");
exit(0);
}
finishtemp=finishtemp->next;
}
printf("/nThe system is in safe status!/n");
printf("/nThe safe sequence is:  /n");
do
{
printf("p%d ",pathhead->value);
}
while(pathhead=pathhead->next);
}

 

操作系统课的实验(银行家算法)#include "malloc.h"   #include "stdio.h"   #include "stdlib.h"   #define alloclen sizeof(struct allocation)   #define maxlen sizeof(struct max)   #define avalen sizeof(struct available)   #define needlen sizeof(struct need)   #define finilen sizeof(struct finish)   #define pathlen sizeof(struct path)   struct allocation   {   int value;   struct allocation *next;   };   struct max   {   int value;   struct max *next;   };   struct available /*可用资源数*/   {   int value;   struct available *next;   };   struct need /*需求资源数*/   {   int value;   struct need *next;   };   struct path   {   int value;   struct path *next;   };   struct finish   {   int stat;   struct finish *next;   };   int main()   {   int row,colum,status=0,i,j,t,temp,processtest;   struct allocation *allochead,*alloc1,*alloc2,*alloctemp;   struct max *maxhead,*maxium1,*maxium2,*maxtemp;   struct available *avahead,*available1,*available2,*workhead,*work1,*work2,*worktemp,*worktemp1;   struct need *needhead,*need1,*need2,*needtemp;   struct finish *finihead,*finish1,*finish2,*finishtemp;   struct path *pathhead,*path1,*path2;   printf("\n请输入系统资源的种类数:");   scanf("%d",&colum);   printf("请输入现时内存中的进程数:");   scanf("%d",&row);   printf("请输入已分配资源矩阵:\n");   for(i=0;i<row;i++)   {   for (j=0;jnext=alloc2->next=NULL;   scanf("%d",&allochead->value);   status++;   }   else   {   alloc2=(struct allocation *)malloc(alloclen);   scanf("%d,%d",&alloc2->value);   if(status==1)   {   allochead->next=alloc2;   status++;   }   alloc1->next=alloc2;   alloc1=alloc2;   }   }   }   alloc2->next=NULL;   status=0;   printf("请输入最大需求矩阵:\n");   for(i=0;i<row;i++)   {   for (j=0;jnext=maxium2->next=NULL;   scanf("%d",&maxium1->value);   status++;   }   else   {   maxium2=(struct max *)malloc(maxlen);   scanf("%d,%d",&maxium2->value);   if(status==1)   {   maxhead->next=maxium2;   status++;   }   maxium1->next=maxium2;   maxium1=maxium2;   }   }   }   maxium2->next=NULL;   status=0;   printf("请输入现时系统剩余的资源矩阵:\n");   for (j=0;jnext=available2->next=NULL;   work1->next=work2->next=NULL;   scanf("%d",&available1->value);   work1->value=available1->value;   status++;   }   else   {   available2=(struct available*)malloc(avalen);   work2=(struct available*)malloc(avalen);   scanf("%d,%d",&available2->value);   work2->value=available2->value;   if(status==1)   {   avahead->next=available2;   workhead->next=work2;   status++;   }   available1->next=available2;   available1=available2;   work1->next=work2;   work1=work2;   }   }   available2->next=NULL;   work2->next=NULL;   status=0;   alloctemp=allochead;   maxtemp=maxhead;   for(i=0;i<row;i++)   for (j=0;jnext=need2->next=NULL;   need1->value=maxtemp->value-alloctemp->value;   status++;   }   else   {   need2=(struct need *)malloc(needlen);   need2->value=(maxtemp->value)-(alloctemp->value);   if(status==1)   {   needhead->next=need2;   status++;   }   need1->next=need2;   need1=need2;   }   maxtemp=maxtemp->next;   alloctemp=alloctemp->next;   }   need2->next=NULL;   status=0;   for(i=0;inext=finish2->next=NULL;   finish1->stat=0;   status++;   }   else   {   finish2=(struct finish*)malloc(finilen);   finish2->stat=0;   if(status==1)   {   finihead->next=finish2;   status++;   }   finish1->next=finish2;   finish1=finish2;   }   }   finish2->next=NULL; /*Initialization compleated*/   status=0;   processtest=0;   for(temp=0;temp<row;temp++)   {   alloctemp=allochead;   needtemp=needhead;   finishtemp=finihead;   worktemp=workhead;   for(i=0;istat==0)   {   for(j=0;jnext,worktemp=worktemp->next)   if(needtemp->valuevalue)   processtest++;   if(processtest==colum)   {   for(j=0;jvalue+=alloctemp->value;   worktemp1=worktemp1->next;   alloctemp=alloctemp->next;   }   if(status==0)   {   pathhead=path1=path2=(struct path*)malloc(pathlen);   path1->next=path2->next=NULL;   path1->value=i;   status++;   }   else   {   path2=(struct path*)malloc(pathlen);   path2->value=i;   if(status==1)   {   pathhead->next=path2;   status++;   }   path1->next=path2;   path1=path2;   }   finishtemp->stat=1;   }   else   {   for(t=0;tnext;   finishtemp->stat=0;   }   }   else   for(t=0;tnext;   alloctemp=alloctemp->next;   }   processtest=0;   worktemp=workhead;   finishtemp=finishtemp->next;   }   }   path2->next=NULL;   finishtemp=finihead;   for(temp=0;tempstat==0)   {   printf("\n系统处于非安全状态!\n");   exit(0);   }   finishtemp=finishtemp->next;   }   printf("\n系统处于安全状态.\n");   printf("\n安全序列为: \n");   do   {   printf("p%d ",pathhead->value);   }   while(pathhead=pathhead->next);   printf("\n");   return 0;   } #include "string.h" #include #include #define M 5 #define N 3 #define FALSE 0 #define TRUE 1 /*M个进程对N类资源最大资源需求量*/ int MAX[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}}; /*系统可用资源数*/ int AVAILABLE[N]={10,5,7}; /*M个进程对N类资源最大资源需求量*/ int ALLOCATION[M][N]={{0,0,0},{0,0,0},{0,0,0},{0,0,0},{0,0,0}}; /*M个进程已经得到N类资源的资源量 */ int NEED[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}}; /*M个进程还需要N类资源的资源量*/ int Request[N]={0,0,0}; void main() { int i=0,j=0; char flag='Y'; void showdata(); void changdata(int); void rstordata(int); int chkerr(int); showdata(); while(flag=='Y'||flag=='y') { i=-1; while(i=M) { printf("请输入需申请资源的进程号(从0到"); printf("%d",M-1); printf(",否则重输入!):"); scanf("%d",&i); if(i=M)printf("输入的进程号不存在,重新输入!\n"); } printf("请输入进程"); printf("%d",i); printf("申请的资源数\n"); for (j=0;jNEED[i][j]) { printf("进程"); printf("%d",i); printf("申请的资源数大于进程"); printf("%d",i); printf("还需要"); printf("%d",j); printf("类资源的资源量!申请不合理,出错!请重新选择!\n"); /*printf("申请不合理,出错!请重新选择!\n");*/ flag='N'; break; } else { if(Request[j]>AVAILABLE[j]) { printf("进程"); printf("%d",i); printf("申请的资源数大于系统可用"); printf("%d",j); printf("类资源的资源量!申请不合理,出错!请重新选择!\n"); /*printf("申请不合理,出错!请重新选择!\n");*/ flag='N'; break; } } } if(flag=='Y'||flag=='y') { changdata(i); if(chkerr(i)) { rstordata(i); showdata(); } else showdata(); } else showdata(); printf("\n"); printf("是否继续银行家算法演示,按'Y'或'y'键继续,按'N'或'n'键退出演示: "); scanf("%c",&flag); } } void showdata() { int i,j; printf("系统可用的资源数为:\n"); printf(" "); for (j=0;j<N;j++){ printf(" 资源"); printf("%d",j); printf(":"); printf("%d",AVAILABLE[j]); /*printf("\n");*/ /* cout<<endl; // cout<<"各进程资源的最大需求量:"<<endl<<endl; // for (i=0;i<M;i++) // { // cout<<"进程"<<i<<":"; // for (j=0;j<N;j++)cout<<" 资源"<<j<<": "<<MAX[i][j]; // cout<<endl; */ } printf("\n"); printf("各进程还需要的资源量:\n"); for (i=0;i<M;i++) { printf(" 进程"); printf("%d",i); printf(":"); for (j=0;j<N;j++){ printf("资源"); printf("%d",j); printf(":"); printf("%d",NEED[i][j]); /*printf("\n");*/ } printf("\n"); } printf("各进程已经得到的资源量: \n"); for (i=0;i<M;i++) { printf(" 进程"); printf("%d",i); /*printf(":\n");*/ for (j=0;j<N;j++){ printf("资源"); printf("%d",j); printf(":"); printf("%d",ALLOCATION[i][j]); /*printf("\n");*/ } printf("\n"); } } void changdata(int k) { int j; for (j=0;j<N;j++) { AVAILABLE[j]=AVAILABLE[j]-Request[j]; ALLOCATION[k][j]=ALLOCATION[k][j]+Request[j]; NEED[k][j]=NEED[k][j]-Request[j]; } }; void rstordata(int k) { int j; for (j=0;j<N;j++) { AVAILABLE[j]=AVAILABLE[j]+Request[j]; ALLOCATION[k][j]=ALLOCATION[k][j]-Request[j]; NEED[k][j]=NEED[k][j]+Request[j]; } }; int chkerr(int s) { int WORK,FINISH[M],temp[M]; int i,j,k=0; for(i=0;i<M;i++)FINISH[i]=FALSE; for(j=0;j<N;j++) { WORK=AVAILABLE[j]; i=s; while(i<M) { if (FINISH[i]==FALSE&&NEED[i][j]<=WORK) { WORK=WORK+ALLOCATION[i][j]; FINISH[i]=TRUE; temp[k]=i; k++; i=0; } else { i++; } } for(i=0;i<M;i++) if(FINISH[i]==FALSE) { printf("\n"); printf("系统不安全!!! 本次资源申请不成功!!!\n"); printf("\n"); return 1; } } printf("\n"); printf("经安全性检查,系统安全,本次分配成功。\n"); printf("\n"); printf(" 本次安全序列:"); for(i=0;i"); } printf("\n"); return 0; }
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