week5-NO.455. Assign Cookies

本文介绍了一个经典的分配问题——分配饼干问题。目标是在给定每个孩子的贪心系数和每块饼干的大小的情况下,最大化满足的孩子数量。文章详细解释了通过排序并匹配饼干与孩子的贪心系数来解决此问题的方法。

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题目

  • Total Accepted: 19294
  • Total Submissions: 40961
  • Difficulty: Easy
  • Contributors: µsic_forever

Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.

Note:
You may assume the greed factor is always positive. 
You cannot assign more than one cookie to one child.

Example 1:

Input: [1,2,3], [1,1]

Output: 1

Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. 
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.

Example 2:

Input: [1,2], [1,2,3]

Output: 2

Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. 
You have 3 cookies and their sizes are big enough to gratify all of the children, 
You need to output 2.
https://leetcode.com/problems/assign-cookies/#/description

思路

题目需要让尽可能多的孩子得到蛋糕

思路是先满足贪心系数低的孩子是最划算的,并且给他能满足他的蛋糕中大小最小的蛋糕也是最划算的。

所以先把两个数组都按从小到大排序,然后按照排序为每一个孩子分配蛋糕,分配给他蛋糕序列中第一个能满足他的蛋糕,即最小的蛋糕。

源程序

class Solution {
public:
    int findContentChildren(vector<int>& g, vector<int>& s) {
        int i,j,t,n = 0,max;
        sort(g.begin(),g.end());
        sort(s.begin(),s.end());
        j = 0;
        for(i = 0;i < g.size();i ++){
            while(j < s.size()){
                if(s[j] >= g[i]){
                    n ++;
                    j ++;
                    break;
                }
                j ++;
            }
        }
        return n;
    }
};


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