题目:
Let's call an array A a mountain if the following properties hold:
A.length >= 3- There exists some
0 < i < A.length - 1such thatA[0] < A[1] < ... A[i-1] < A[i] > A[i+1] > ... > A[A.length - 1]
Given an array that is definitely a mountain, return any i such that A[0] < A[1] < ... A[i-1] < A[i] > A[i+1] > ... > A[A.length - 1].
Example 1:
Input: [0,1,0] Output: 1
Example 2:
Input: [0,2,1,0] Output: 1
Note:
3 <= A.length <= 10000- 0 <= A[i] <= 10^6
- A is a mountain, as defined above.
代码:
class Solution {
public:
int peakIndexInMountainArray(vector<int>& A) {
int i = 0;
int peak;
while(i < A.size()-1 && A[i] < A[i+1]) i++;
return i;
//while(i < A.size()-1 && A[i] > A[i+1]) i++;
//if(i == A.size()-1) return
}
};
本文介绍了一种算法,用于在给定的山脉数组中找到顶峰的位置。通过遍历数组并比较相邻元素,该算法能有效地确定顶点的索引。
416

被折叠的 条评论
为什么被折叠?



