https://leetcode.com/problems/majority-element/
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.
You may assume that the array is non-empty and the majority element always exist in the array.
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
public class Solution {
public int majorityElement(int[] nums) {
Arrays.sort(nums);
return nums[(nums.length-1)/2];
}
}
public class Solution {
public int majorityElement(int[] nums) {
int major = nums[0]; int count = 1;
for(int i = 1; i<nums.length; i++){
if(count == 0) major = nums[i];
if(nums[i]==major) count++;
else count--;
}
return major;
}
}Because the major num occurs more than half of the length of the nums, this solution can always work.
本文介绍了一种寻找多数元素的方法,该元素在数组中出现次数超过一半。通过排序或使用Boyer-Moore投票算法来实现解决方案。

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