How to return a long columns size

本文介绍了一个PL/SQL函数getLongsize,该函数用于查询并返回Oracle数据库中长字段的实际大小。通过使用dbms_sql包,此函数能够有效处理长字段的数据检索,避免了因字段过长而引发的问题。

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create or replace function getLongsize (p_query varchar2) return number as
  v_cursor         integer default dbms_sql.open_cursor;
  i                number;
  v_temp           varchar2(250);
  v_returned_size  number;
  v_buffer_size    number := 250;
  v_marker         number := 0;
begin
  dbms_sql.parse( v_cursor, p_query, dbms_sql.native );
  dbms_sql.define_column_long(v_cursor, 1);
  i := dbms_sql.execute(v_cursor);
  if (dbms_sql.fetch_rows(v_cursor)>0) then
    loop
      dbms_sql.column_value_long(v_cursor, 1, v_buffer_size, v_marker , v_temp, v_returned_size );
      v_marker := v_marker + v_returned_size;
      exit when v_returned_size = 0;
    end loop;
  end if;
  return v_marker;
end;

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

 select owner, view_name,
       getLongsize ('select text from dba_views where owner=''SYS'' and view_name=''ALL_OBJECTS''')  long_size
from dba_views
where view_name='ALL_OBJECTS';

OWNER VIEW_NAME LON_SIZE
-----   ---------       --------
SYS ALL_OBJECTS 9039

Implement the classic method for composing secret messages called a square code. Given an English text, output the encoded version of that text. First, the input is normalized: the spaces and punctuation are removed from the English text and the message is down-cased. Then, the normalized characters are broken into rows. These rows can be regarded as forming a rectangle when printed with intervening newlines. For example, the sentence ```text "If man was meant to stay on the ground, god would have given us roots." ``` is normalized to: ```text "ifmanwasmeanttostayonthegroundgodwouldhavegivenusroots" ``` The plaintext should be organized into a rectangle as square as possible. The size of the rectangle should be decided by the length of the message. If `c` is the number of columns and `r` is the number of rows, then for the rectangle `r` x `c` find the smallest possible integer `c` such that: - `r * c >= length of message`, - and `c >= r`, - and `c - r <= 1`. Our normalized text is 54 characters long, dictating a rectangle with `c = 8` and `r = 7`: ```text "ifmanwas" "meanttos" "tayonthe" "groundgo" "dwouldha" "vegivenu" "sroots " ``` The coded message is obtained by reading down the columns going left to right. The message above is coded as: ```text "imtgdvsfearwermayoogoanouuiontnnlvtwttddesaohghnsseoau" ``` Output the encoded text in chunks that fill perfect rectangles `(r X c)`, with `c` chunks of `r` length, separated by spaces. For phrases that are `n` characters short of the perfect rectangle, pad each of the last `n` chunks with a single trailing space. ```text "imtgdvs fearwer mayoogo anouuio ntnnlvt wttddes aohghn sseoau " ``` 上述为题目要求,请用C语言实现,函数声明如下: char *ciphertext(const char *input)
最新发布
08-13
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