Leetcode-3-Longest Substring Without Repeating Characters

本文介绍了一种求解字符串中最长无重复字符子串长度的方法,并提供了完整的Java实现代码。通过滑动窗口的方式,利用ASCII码对应的数组来标记字符出现情况,高效地解决了这一常见算法问题。

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题目描述

Given a string, find the length of the longest substring without repeating characters.

Examples:

Given “abcabcbb”, the answer is “abc”, which the length is 3.

Given “bbbbb”, the answer is “b”, with the length of 1.

Given “pwwkew”, the answer is “wke”, with the length of 3. Note that the answer must be a substring, “pwke” is a subsequence and not a substring.

/**
 * Longest Substring Without Repeating Characters
 * 
 * @author jiaohanhan
 *
 */
public class P3 {

    public static void main(String[] args) {
        P3 p3 = new P3();
        System.out.println(p3.lengthOfLongestSubstring("abcabcbb"));
        System.out.println(p3.lengthOfLongestSubstring("bbbb"));
        System.out.println(p3.lengthOfLongestSubstring("pwwkew"));

    }

    public int lengthOfLongestSubstring(String s) {
        int[] map = new int[256]; // ASCII码

        int j = 0;
        int i = 0;
        int ans = 0;
        for (; i < s.length(); i++) {
            while (j < s.length() && map[s.charAt(j)] == 0) {
                map[s.charAt(j)] = 1;
                ans = Math.max(ans, j - i + 1);
                j++;
            }
            map[s.charAt(i)] = 0;
        }

        return ans;
    }

}

这里写图片描述

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