使用 ajax 提交数据

 

 

 

<!--<br /><br />Code highlighting produced by Actipro CodeHighlighter (freeware)<br />http://www.CodeHighlighter.com/<br /><br />--> var  Ajax  =  {

    xmlHttp: "" ,
    getYear: function (){
       return   document.getElementById( " SY " ).selectedIndex + 1900 + "" ;
    },
    getMonth:  function  (){
       return   document.getElementById( " SM " ).selectedIndex + 1 + "" ;
    },
 createXMLHttpRequest: function  () {
       if  (window.ActiveXObject) {
          xmlHttp  =   new  ActiveXObject( " Microsoft.XMLHTTP " );
      }
       else   if  (window.XMLHttpRequest) {
          xmlHttp  =   new  XMLHttpRequest();
      }
 },
 send: function  () {
    this .createXMLHttpRequest();
   xmlHttp.onreadystatechange  =   this .showResponse;
   xmlHttp.open( " POST " ,  " DateSetAjax.action?toShowYearMonth= " +  leftPad( this .getYear ()) + " - " + leftPad( this .getMonth()),  false );
   xmlHttp.send( " yearmonth=aa " );
 },
 showResponse: function (){
     if (xmlHttp.readyState  ==   4 ) {
       if (xmlHttp.status  ==   200 ) {  
        var  data  =   xmlHttp.responseText;
        if (data == " null " )
         data  =   "" ;
       CLD.date1.value = data;
    }
   }
 }


}

 

Ajax.send(); 发送请求。

 上面代码 参数必须在附在url 后面 才能在struts2中取到。xmlHttp.send("yearmonth=aa"); 中的参数并不起作用。

send 怎么发送数据呢

ServletActionContext.getRequest().getParameter(key); ok

ActionContext.getContext().get("request").get(key);  null.