Lake Counting (P2386)

是简单的搜索题,可以深搜,也可以广搜。这里用的是深搜

记得要标记状态就行了。


#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>

using namespace std;


#define N 105

int n,m;

char map[N][N];
bool vist[N][N];

int a[8][2]={{1,0},{1,1},{0,1},{-1,1},{-1,0},{-1,-1},{0,-1},{1,-1}};

bool in(int i,int j)
{
	if (i>=0&&i<n&&j>=0&&j<m)
		return true;
	return false;
}

void bfs(int i,int j)
{
	vist[i][j]=true;
	int k;
	for (k=0;k<9;k++)
	{
		int x=i+a[k][0];
		int y=j+a[k][1];
		if (in(x,y)&&map[x][y]=='W'&&!vist[x][y])
			bfs(x,y);
	}
}

int  main()
{
	freopen("in.txt","r",stdin);
	int i,j,k;
	cin>>n>>m;
	for (i=0;i<n;i++)
	{
		cin>>map[i];
	}
	int ans=0;

	memset(vist,false,sizeof(vist));

	for (i=0;i<n;i++)
	{
		for (j=0;j<m;j++)  if (map[i][j]=='W'&&!vist[i][j])
		{
			bfs(i,j);
			ans++;
		}
	}

	cout<<ans<<endl;
}

Lake Counting
Time Limit: 1000MS Memory Limit: 65536K
Total Submissions: 14593 Accepted: 7391

Description

Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water ('W') or dry land ('.'). Farmer John would like to figure out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors.

Given a diagram of Farmer John's field, determine how many ponds he has.

Input

* Line 1: Two space-separated integers: N and M

* Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have spaces between them.

Output

* Line 1: The number of ponds in Farmer John's field.

Sample Input

10 12
W........WW.
.WWW.....WWW
....WW...WW.
.........WW.
.........W..
..W......W..
.W.W.....WW.
W.W.W.....W.
.W.W......W.
..W.......W.

Sample Output

3

Hint

OUTPUT DETAILS:

There are three ponds: one in the upper left, one in the lower left,and one along the right side.

Source



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