[Leetcode]#165 Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not “two and a half” or “half way to version three”, it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

//#165 Compare Version Numbers
//8ms 2.02%
class Solution {
public:
    int compareVersion(string version1, string version2) 
    {
        vector<int> version_number1 = getVersionNumber(version1);
        vector<int> version_number2 = getVersionNumber(version2);
        return compareVersionNumber(version_number1, version_number2);
    }

    int compareVersionNumber(vector<int> version_number1, vector<int> version_number2)
    {
        int compare1(0), compare2(0);
        for(unsigned int i=0; i<version_number1.size() || i<version_number2.size(); i++)
        {
            if(i >= version_number1.size())
            {
                compare1 = 0;
            }
            else
            {
                compare1 = version_number1[i];
            }
            if(i >= version_number2.size())
            {
                compare2 = 0;
            }
            else
            {
                compare2 = version_number2[i];
            }
            //cout << "compare1: " << compare1 << ", compare2: " << compare2 << endl;
            if(compare1 > compare2)
            {
                return 1;
            }
            else if(compare1 < compare2)
            {
                return -1;
            }
        }
        return 0;
    }

    vector<int> getVersionNumber(string s)
    {
        vector<int> result;
        int value(0);
        unsigned int i(0);
        for(i=0; i<s.size(); i++)
        {
            if(s[i] != '.')
            {
                value = value * 10 + int(s[i] - '0');
            }
            else
            {
                cout << "value: " << value << endl;
                result.push_back(value);
                value = 0;
            }
        }   
        if(value != 0)
        {
            cout << "value: " << value << endl;
            result.push_back(value);
        }
        return result;
    }
};