关于SSH 用户注册的例子

最新推荐文章于 2018-07-27 15:12:24 发布

最新推荐文章于 2018-07-27 15:12:24 发布 · 207 阅读

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本文记录了作者集成Struts2、Spring和Hibernate（SSH）的过程及解决遇到的问题，包括配置文件、DAO实现与Struts2表单处理等关键步骤。

这两天一直在集成SSH，错误百出今天终于搞定了菜鸟一个呵呵
之前是先把struts2和spring集成了然后把spring和hibernate集成了大概知道怎么回事之后今天终于搞定了

/**
 * @author jeedroid
 */
package com.jeedroid.dao;

import com.jeedroid.model.User;

public interface UserDao
{
public abstract boolean addUser(User user);
}

package com.jeedroid.daoimpl;

import org.hibernate.SessionFactory;
import org.springframework.dao.DataAccessException;
import org.springframework.orm.hibernate3.HibernateTemplate;

import com.jeedroid.dao.UserDao;
import com.jeedroid.model.User;

public class UserDaoImpl implements UserDao
{
	private SessionFactory sessionFactory;


	public void setSessionFactory(SessionFactory sessionFactory)
	{
		this.sessionFactory = sessionFactory;
	}

	@Override
	public boolean addUser(User user)
	{
		try {
			HibernateTemplate hibernateTemplate =new HibernateTemplate(sessionFactory);
			hibernateTemplate.saveOrUpdate(user);
			return true;
		} catch (DataAccessException e) {
			e.printStackTrace();
			return false;
		}

	}

}

/**
 * @author jeedroid
 */
package com.jeedroid.action;

import com.jeedroid.daoimpl.UserDaoImpl;
import com.jeedroid.model.User;
import com.opensymphony.xwork2.ActionSupport;

public class RegisterAction extends ActionSupport
{
private User user;
private UserDaoImpl userDaoImpl;

public User getUser()
{
	return user;
}

public void setUser(User user)
{
	this.user = user;
}

public void setUserDaoImpl(UserDaoImpl userDaoImpl)
{
	this.userDaoImpl = userDaoImpl;
}

@Override
public String execute() throws Exception
{
	if(userDaoImpl.addUser(user))
			return SUCCESS;
	else
		return INPUT;
}

}

<struts>

<constant name="struts.enable.DynamicMethodInvocation" value="false" />
<constant name="struts.devMode" value="true" />

<package name="struts2" extends="struts-default">
<action name="register" class="registerAction">
<result name="success">/success.jsp</result>
<result name="input">/register.jsp</result>
</action>
</package>

</struts>

applicationContext.xml:
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName">
<value>com.mysql.jdbc.Driver</value>
</property>
<property name="url">
<value>jdbc:mysql://localhost:3306/spring_hibernate</value>
</property>
<property name="username">
<value>root</value>
</property>
<property name="password">
<value>123321</value>
</property>
</bean>

<bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource">
<ref local="dataSource"/>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQL5Dialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
<property name="mappingResources">
<list>
<value>com/jeedroid/model/User.hbm.xml</value>
</list>
</property>
</bean>

<bean id="userDaoImpl" class="com.jeedroid.daoimpl.UserDaoImpl">
<property name="sessionFactory">
<ref bean="sessionFactory"/>
</property>
</bean>

<bean id="registerAction" class="com.jeedroid.action.RegisterAction">
<property name="userDaoImpl">
<ref local="userDaoImpl"/>
</property>
</bean>

之前一直报attempt to create saveOrUpdate event with null entity这个错误，后来把User.java里的含参构造函数去掉就行了应该是struts2传值过来时实例化的问题

只是一个简单的用户注册没有加事务了什么的看看就行了呵呵