字符串简单处理
#include<iostream>
#include<string>
using namespace std;
int main(){
string str;
int sum,k,i;
while(cin>>str){
sum=0,k=10,i=0;
while(k!=1){
if(str[i]!='-'){
sum += (str[i] - '0' ) * k;
--k;
}
++i;
}
int mod = 11 - sum % 11;
if(mod == 11) mod=0;
if(mod!=10){
cout<<str<<'-'<<mod<<endl;
}
else
cout<<str<<"-X\n";
}
return 0;
}