Android 获取AndroidManifest.xml文件versionCode，versionName属性

获取versionCode,versionName属性
String pName = "cn.nedu.math.ninebox";

try {

       packagemanager pm = getpackagemanager();

         PackageInfo pinfo = pm.getPackageInfo(pName, PackageManager.GET_CONFIGURATIONS);
        String versionCode = pinfo.versionName;
        Strint versionName = pinfo.versionCode;
} catch (NameNotFoundException e) {
}
AndroidManifest.xml文件如下
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android=" http://schemas.android.com/apk/res/android"
       package="cn.nedu.math.ninebox"
      android:versionCode="1"
      android:versionName="1.0">
    <application android:icon="@drawable/icon" android:label="@string/app_name">
        <activity android:name=".NineBox"
                  android:label="@string/app_name">
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
    </application>
    <uses-sdk android:minSdkVersion="3" />

</manifest>

添加： pName可以用Context.gerPackageName()取得packageName.

转：http://hi.baidu.com/sunboy_2050/blog/item/c57baf0dec6850f7aa6457e0.html