Attempt to present on whose view is not in the window hierarchy!

最新推荐文章于 2020-07-21 21:03:45 发布

jackshiny

最新推荐文章于 2020-07-21 21:03:45 发布

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分类专栏： ios

本文链接：https://blog.youkuaiyun.com/jackshiny/article/details/50846682

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本文详细阐述了一个在ViewController中直接跳转到另一个ViewController导致窗口层次结构混乱的问题，并提供了解决方案。通过将跳转操作从viewDidLoad移至viewDidAppear，避免了错误的层级显示。解决方案确保了应用程序的稳定性和用户体验。

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Attempt to present on whose view is not in the window hierarchy!

- (void)viewDidLoad {
    [super viewDidLoad];
    UIStoryboard *story = [UIStoryboard storyboardWithName:@"Storyboard" bundle:nil];
    UIViewController *controller = [story instantiateViewControllerWithIdentifier:@"RootViewController"];
    [self presentViewController:controller animated:YES completion:nil];
}

上面代码中的问题是在controller a的viewDidLoad里面直接跳转controller b，然后导致在显示controller b的时候也调用了controller a来显示，然后发现这个window的层次结构就错乱了。
参考：stackoverflow给出的回答

我的解决方案是：等到viewcontroller 显示完之后再跳转

- (void)viewDidAppear:(BOOL)animated {
    [super viewDidAppear:animated];
    UIStoryboard *story = [UIStoryboard storyboardWithName:@"Storyboard" bundle:nil];
    UIViewController *controller = [story instantiateViewControllerWithIdentifier:@"RootViewController"];
    [self presentViewController:controller animated:YES completion:nil];
}