【无标题】蒜头的进制转换

#include <bits/stdc++.h>
using namespace std;
int s[40];
int s1[40];

char s2[20] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
//因为大于等于10的数要以字母的形式输出

int main() {
	int x, n, m;
	int sum = 0;
	cin >> x >> n >> m;
	while (x >= n) {
		s[sum++] = x % n;
		x = x / n;
	}
	s[sum] = x;
	int anx = 0;
	for (int i = 0; i <= sum; i++) {        //算出翻转后的10进制数
		anx = anx * n + s[i];
	}
	sum = 0;
	while (anx >= m) {
		s1[sum++] = anx % m;
		anx = anx / m;
	}
	s1[sum] = anx;
	for (int i = sum; i >= 0; i--) {
		cout << s2[s1[i]];
	}
	return 0;
}