只提供(*+><等运算其他要只写)其他要自己写!!!
#include<cstdio>
#include<iostream>
#include<string.h>
using namespace std;
const int maxn = 200;
struct bign{
int len, s[maxn];
bign() {
memset(s, 0, sizeof(s));
len = 1;
}
bign(int num) {
*this = num;
}
bign(const char* num) {
*this = num;
}
bign operator = (int num) {//直接以整数赋值
char s[maxn];
sprintf(s, "%d", num);
*this = s;
return *this;
}
bign operator = (const char* num) {//以字符串赋值
len = strlen(num);
for(int i = 0; i < len; i++) s[i] = num[len-i-1] - '0';
return *this;
}
string str() const {//将bign转化成字符串
string res = "";
for(int i = 0; i < len; i++) res = (char)(s[i] + '0') + res;
if(res == "") res = "0";
return res;
}
bign operator + (const bign& b) const{//重载+号运算
bign c;
c.len = 0;
for(int i = 0, g = 0; g || i < max(len, b.len); i++) {
int x = g;
if(i < len) x += s[i];
if(i < b.len) x += b.s[i];
c.s[c.len++] = x % 10;
g = x / 10;
}
return c;
}
void clean() {//去掉前到0
while(len > 1 && !s[len-1]) len--;
}
bign operator * (const bign& b) {//重载*号运算
bign c; c.len = len + b.len;
for(int i = 0; i < len; i++)
for(int j = 0; j < b.len; j++)
c.s[i+j] += s[i] * b.s[j];
for(int i = 0; i < c.len-1; i++){
c.s[i+1] += c.s[i] / 10;
c.s[i] %= 10;
}
c.clean();
return c;
}
bign operator - (const bign& b) {//重载-号运算
bign c; c.len = 0;
for(int i = 0, g = 0; i < len; i++) {
int x = s[i] - g;
if(i < b.len) x -= b.s[i];
if(x >= 0) g = 0;
else {
g = 1;
x += 10;
}
c.s[c.len++] = x;
}
c.clean();
return c;
}
bool operator < (const bign& b) const{//重载<号运算
if(len != b.len) return len < b.len;
for(int i = len-1; i >= 0; i--)
if(s[i] != b.s[i]) return s[i] < b.s[i];
return false;
}
bool operator > (const bign& b) const{//重载>号运算
return b < *this;
}
bool operator <= (const bign& b) {//重载<=号运算
return !(b > *this);
}
bool operator == (const bign& b) {//重载>=号运算
return !(b < *this) && !(*this < b);
}
bign operator += (const bign& b) {//重载+=号运算
*this = *this + b;
return *this;
}
};
istream& operator >> (istream &in, bign& x) {//重载输入运算符
string s;
in >> s;
x = s.c_str();
return in;
}
ostream& operator << (ostream &out, const bign& x) {//重载输出运算符
out << x.str();
return out;
}
int main() {
bign a;
cin >> a;
a += "123456789123456789000000000";
a=a*1000000000;
cout << a << endl;
return 0;
}
大数除法!!!!!
//注:此算法是用字符串处理的,等有空的时候在改成bign类型
void Div(char *str1, char *str2, char *str3){
int i1, i2, i, j, jj, tag, carry, cf, c[MAXSIZE];
int len1 = strlen(str1), len2 = strlen(str2), lend;
char d[MAXSIZE];
memset(c, 0, sizeof(c));
memcpy(d, str1, len2); //把从str1指向的串复制len2长度到d指向的内容;
lend = len2; j = 0;
for( i1=len2-1; i1 < len1; ++i1 ){
if( lend < len2 ){
d[lend] = str1[i1+1]; c[j] = 0;
++j; ++lend;
}
else if( lend == len2 ){
jj = 1;
for( i=0; i < lend; ++i ){
if( d[i] > str2[i] ) break;
else if( d[i] < str2[i] ){
jj = 0; break;
}
}
if( jj == 0 ){
d[lend] = str1[i1+1]; c[j] = 0;
++j; ++lend;
continue;
}
}
if( jj==1 || lend > len2 ){
cf = jj=0;
while( d[jj] <= '0' && jj < lend ) ++jj;
if( lend-jj > len2 ) cf = 1;
else if( lend-jj < len2 ) cf = 0;
else{
i2 = 0; cf = 1;
for( i=jj; i < lend; ++i ){
if( d[i] < str2[i2] ){
cf = 0; break;
}
else if( d[i] > str2[i2] ){
break;
}
++i2;
}
}//else
while( cf ){
i2 = len2-1; cf = 0;
for( i=lend-1; i >= lend-len2; --i ){
d[i] = d[i]-str2[i2]+'0';
if( d[i] < '0' ){
d[i] = d[i]+10; carry = 1;
--d[i-1];
}
else carry = 0;
--i2;
}
++c[j]; jj=0;
while( d[jj] <= '0' && jj < lend ) ++jj;
if( lend-jj > len2 ) cf = 1;
else if( lend-jj < len2 ) cf = 0;
else{
i2 = 0; cf = 1;
for( i=jj; i < lend; ++i ){
if( d[i] < str2[i2] ){
cf = 0; break;
}
else if( d[i] > str2[i2] ){
break;
}
++i2;
}
}//else
}//while
jj = 0;
while( d[jj] <= '0' && jj < lend ) ++jj;
for( i=0;i < lend-jj; ++i ) d[i] = d[i+jj];
d[i] = str1[i1+1]; lend = i+1;
++j;
}//else
}//for
i = tag = 0;
while( c[i] == 0 ) ++i;
for( ; i < j; ++i, ++tag ) str3[tag] = c[i]+'0';
str3[tag] = '/0';
}