今天在做jqGrid例子时,发现Array Data有个问题,写下来问问大家
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<head>
<meta http-equiv="Content-Type" content="text/html; charset=gbk" />
<title>jqGrid Demos</title>
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<link rel="stylesheet" type="text/css" media="screen" href="themes/ui.jqgrid.css" />
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<script type="text/javascript">
$.jgrid.no_legacy_api = true;
$.jgrid.useJSON = true;
</script>
<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>
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<script src="js/ui.multiselect.js" type="text/javascript"></script>
<script type="text/javascript">
jQuery(document).ready(function(){
jQuery("#list4").jqGrid({
datatype: "local",
height: 250,
colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
colModel:[
{name:'id',index:'id', width:60, sorttype:"int"},
{name:'invdate',index:'invdate', width:90, sorttype:"date"},
{name:'name',index:'name', width:100},
{name:'amount',index:'amount', width:80, align:"right",sorttype:"float"},
{name:'tax',index:'tax', width:80, align:"right",sorttype:"float"},
{name:'total',index:'total', width:80,align:"right",sorttype:"float"},
{name:'note',index:'note', width:150, sortable:false}
],
multiselect: true,
caption: "Manipulating Array Data"
});
var mydata = [
{id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
{id:"2",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
{id:"3",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
{id:"4",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
{id:"5",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
{id:"6",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
{id:"7",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
{id:"8",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
{id:"9",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}
];
for(var i=0;i<=mydata.length;i++)
//jqgrid_demo35中用这个方法,发现不能加载数据
// jQuery("#list4").jqGrid('addRowData',i+1,mydata[i]);
//我改用以下方法就可以成功加载,不知为什么?还请高手指点???
jQuery("#list4").addRowData(i+1,mydata[i]);
});
</script>
<body>
<table id="list4"></table>
</body>
</html>
本文探讨了使用jqGrid插件加载本地数据时遇到的问题。具体表现为ArrayData中使用特定方法无法正常加载数据到表格中。通过对比不同方法,找到了可行的解决方案,并寻求社区的帮助以理解背后的原因。
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