/* THE PROGRAM IS MADE BY PYY */
/*----------------------------------------------------------------------------//
Copyright (c) 2011 panyanyany All rights reserved.
URL : http://acm.hdu.edu.cn/showproblem.php?pid=1305
Name : 1305 Immediate Decodability
Date : Wednesday, August 24, 2011
Time Stage : half an hour
Result:
4486760 2011-08-24 21:16:51 Accepted 1305
0MS 240K 1929 B
C++ pyy
Test Data:
Review:
//----------------------------------------------------------------------------*/
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define max(a, b) (((a) > (b)) ? (a) : (b))
#define min(a, b) (((a) < (b)) ? (a) : (b))
#define infinity 0x0f0f0f0f
#define minus_inf 0x80808080
#define MAXSIZE 1009
typedef struct tagNODE {
int cnt ;
struct tagNODE * child[2] ;
} NODE ;
char str[22] ;
int can ;
int stkPtr ;
NODE * stack[MAXSIZE] ;
NODE * tmp, * newNode ;
#define root stack[0]
void insert (char *patn)
{
int i, j ;
int len = strlen (patn) ;
tmp = root ;
for (i = 0 ; i < len - 1 ; ++i)
{
j = patn[i] - '0' ;
if (!tmp->child[j])
{
newNode = (NODE *) calloc (1, sizeof (NODE)) ;
stack[stkPtr++] = newNode ;
tmp->child[j] = newNode ;
}
tmp = tmp->child[j] ;
if (tmp->cnt)
can = 0 ;
}
// 我用的判断方法貌似不太美观,看了下别人的代码,
// 通过判断下一层的孩子指针是否存在,可以达到同样的效果
j = patn[i] - '0' ;
if (tmp->child[j])
{
can = 0 ;
}
else
{
newNode = (NODE *) calloc (1, sizeof (NODE)) ;
stack[stkPtr++] = newNode ;
tmp->child[j] = newNode ;
}
tmp = tmp->child[j] ;
++tmp->cnt ;
}
void recycle ()
{
while (stkPtr)
free (stack[--stkPtr]) ;
}
int main ()
{
int i, j, tmp, tcase ;
tcase = 0 ;
while (scanf ("%s", str) != EOF)
{
can = 1 ;
stkPtr = 1 ;
root = (NODE *) calloc (1, sizeof (NODE)) ;
insert (str) ;
while (scanf ("%s", str), *str != '9')
insert (str) ;
if (can)
printf ("Set %d is immediately decodable\n", ++tcase) ;
else
printf ("Set %d is not immediately decodable\n", ++tcase) ;
recycle () ;
}
return 0 ;
}