水题啊~~~
/* THE PROGRAM IS MADE BY PYY */ /*----------------------------------------------------------------------------// http://acm.hdu.edu.cn/showproblem.php?pid=2001 计算两点间的距离 Date : 2011/2/27 Thursday Begin : 15:00 End : 15:18 //----------------------------------------------------------------------------*/ #include <iostream> #include <cmath> #include <stdlib.h> #include <iomanip> #define powerp(a, b) (abs(a - b)*abs(a - b)) using namespace std; int main() { double a, b, c, d; while (cin >> a >> b >> c >> d) { cout << setprecision(2) << fixed << sqrt(powerp(a, c) + powerp(b, d)) << endl; } return 0; }
======================================原题如下======================================
计算两点间的距离
Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 33635Accepted Submission(s): 12588