网上找了很多例子,看了很多资料发现都不能完全重现一个OSGi的Web
Demo
本文结合了《OSGi原理与最佳实践》+公司同事的《OSGi开发》+自己的理解。
环境WindowXP + eclipse3.4 +
Spring OSGi1.2.1
1. 创建timeservice Bundle,提供输出时间的功能
1.1 eclipse内创建Maven
Project,选quickstart project:timeservice,package
org.osgichina.demo.timeservice
1.2 创建好后,remove
maven的jar包,删掉project中的App和AppTest,在项目上右键->PDE Tools->Convert
1.3
public interface TimeService {
String getCurrentTime();
}
public String getCurrentTime() {
return ( new Date()).toString();
}
}
1.4
Spring配置
配置放在META-INF/spring目录下,框架启动时会按照这个路径去寻找配置文件
timeservice.xml
< beans xmlns ="http://www.springframework.org/schema/beans"
xmlns:xsi ="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation ="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd" >
<!-- timeService bean -->
< bean name ="timeService" class ="org.osgichina.demo.timeservice.impl.TimeServiceImpl" />
</ beans >
timeservice-osgi.xml
< beans xmlns ="http://www.springframework.org/schema/beans"
xmlns:xsi ="http://www.w3.org/2001/XMLSchema-instance" xmlns:osgi ="http://www.springframework.org/schema/osgi"
xsi:schemaLocation ="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/osgi http://www.springframework.org/schema/osgi/spring-osgi.xsd" >
<!-- 将timeService 这个bean发布为OSGi服务的定义 -->
< osgi:service id ="osgiTimeService" ref ="timeService" interface ="org.osgichina.demo.timeservice.TimeService" >
</ osgi:service >
</ beans >
这个Bundle到此已经完成了,下一节会讲解helloworldweb
Bundle,涉及Import Package,OSGi的启动,Spring+Web的配置等
专注于Java,数据库性能,Web
Server负载,数据挖掘,机器学习等方向