1、导入jar包
2、配置web.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "dtd\web-app_2_3.dtd">
<web-app>
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>2</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>2</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
3、配置struts-config.xml文件,放在WEB-INF目录下
<!DOCTYPE struts-config PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 1.2//EN" "http://jakarta.apache.org/struts/dtds/struts-config_1_2.dtd">
<struts-config>
<form-beans>
<form-bean name="userinfo" type="test.UserInfoBean"/>
</form-beans>
<global-forwards>
<forward name="success" path="/test/success.jsp" redirect="false" />
</global-forwards>
<action-mappings>
<action path="/login" type="test.TestAction" name="userinfo"/>
</action-mappings>
</struts-config>
4、登录页面
<form id="userinfo" name="userinfo" action="<%=request.getContextPath()%>/login.do" method="post">
用户名:<input id="username" type="text" name="userName"/><br/>
密 码:<input id="password" type="password" name="password"/><br/>
<input id="submit" type="submit" value="登 录"/>
</form>
5、Action:继承org.apache.struts.action.Action,重写execute()方法
6、Bean需要继承org.apache.struts.action.ActionForm
本文详细介绍了如何使用Struts框架配置Web应用,包括导入jar包、配置web.xml文件、配置struts-config.xml文件、登录页面设计、Action类实现及Bean继承等关键步骤。
2276

被折叠的 条评论
为什么被折叠?



