题:对于下图的二叉树,输出其嵌套括号表示
[img]http://dl.iteye.com/upload/attachment/0072/3033/114e5346-bf3e-3bf5-b696-7bfbf260a382.gif[/img]
程序运行结果:
[color=blue][b]H(D(B(,A),C),G(,F(E)))[/b][/color]
[img]http://dl.iteye.com/upload/attachment/0072/3033/114e5346-bf3e-3bf5-b696-7bfbf260a382.gif[/img]
import java.util.*;
public class BinaryTree {
protected Node root;
public BinaryTree(Node root) {
this.root = root;
}
public Node getRoot() {
return root;
}
/** 构造树 */
public static Node init() {
Node a = new Node('A');
Node b = new Node('B', null, a);
Node c = new Node('C');
Node d = new Node('D', b, c);
Node e = new Node('E');
Node f = new Node('F', e, null);
Node g = new Node('G', null, f);
Node h = new Node('H', d, g);
return h;// root
}
/** 访问节点 */
public static void visit(Node p) {
System.out.print(p.getKey() + " ");
}
/** 递归实现前序遍历 */
static void preorder(Node p) {
if (p != null) {
visit(p);
preorder(p.getLeft());
preorder(p.getRight());
}
}
/** 层次遍历*/
static void levelorder(Node p){
if(p==null) return;
Queue<Node> queue=new LinkedList<Node>();
queue.offer(p);
while(queue.size()>0){
Node temp=queue.poll();
visit(temp);
if(temp.getLeft()!=null){
queue.offer(temp.getLeft());
}
if(temp.getRight()!=null){
queue.offer(temp.getRight());
}
}
}
//输出二叉树的嵌套括号表示
static void display(Node tree){
if(tree!=null){
System.out.printf("%c",tree.getKey());
if(tree.getLeft()!=null||tree.getRight()!=null){
System.out.printf("(");
display(tree.getLeft());
if(tree.getRight()!=null)
System.out.printf(",");
display(tree.getRight());
System.out.printf(")");
}
}
}
/**
* @param args
*/
public static void main(String[] args) {
BinaryTree tree = new BinaryTree(init());
display(tree.getRoot());
}
}
public class Node {
private char key;
private Node left, right;
public Node(char key) {
this(key, null, null);
}
public Node(char key, Node left, Node right) {
this.key = key;
this.left = left;
this.right = right;
}
public char getKey() {
return key;
}
public void setKey(char key) {
this.key = key;
}
public Node getLeft() {
return left;
}
public void setLeft(Node left) {
this.left = left;
}
public Node getRight() {
return right;
}
public void setRight(Node right) {
this.right = right;
}
}
程序运行结果:
[color=blue][b]H(D(B(,A),C),G(,F(E)))[/b][/color]