table
id name
1 a
2 b
3 c
4 c
5 b
select *, count(distinct name) from table group by name
结果:
id name count(distinct name)
1 a 1
2 b 1
3 c 1
或则
group_concat(distinct name)配合group by name
table
id name
1 a
2 b
3 c
4 c
5 b
select *, count(distinct name) from table group by name
结果:
id name count(distinct name)
1 a 1
2 b 1
3 c 1
或则
group_concat(distinct name)配合group by name