1149: Binary Numbers
| Result | TIME Limit | MEMORY Limit | Run Times | AC Times | JUDGE |
|---|---|---|---|---|---|
| 3s | 8192K | 1690 | 653 | Standard |
Given a positive integer n, nd the positions of all 1's in its binary representation. The position of the least significant bit is 0.
Example
The positions of 1's in the binary representation of 13 are 0, 2, 3.
Task
Write a program which for each data set:
reads a positive integer n,
computes the positions of 1's in the binary representation of n,
writes the result.
Input
The first line of the input contains exactly one positive integer d equal to the number of data sets, 1 <= d <= 10. The data sets follow.Each data set consists of exactly one line containing exactly one integer n, 1 <= n <= 10^6.
Output
The output should consists of exactly d lines, one line for each data set.Line i, 1 <= i <= d, should contain increasing sequence of integers separated by single spaces - the positions of 1's in the binary representation of the i-th input number.
Sample Input
1 13
Sample Output
0 2 3
/*
水题
最基本的移位操作
*/
#include <stdio.h>
int d = 0,n;
int main()
{
scanf("%d",&d);
for(int i=0;i<d;i++)
{
scanf("%d",&n);
if(n == 0)
{
printf("0\n");
continue;
}
int j = 0;
while(n != 0)
{
if(n & 1 == 1 && n != 1) //表示末位是否为1
{
printf("%d ",j);
}
if(n == 1)
printf("%d",j);
n = n >>1; //移位
j++;
}
printf("\n");
}
return 0;
}
水题一个,但是关键是最后一个j输出的时候只能是输出数字,不能多输出一个空格,否则会PE错误。
所以n == 1 的时候要特殊处理
本文深入探讨了使用基本的移位操作来解决位运算问题的方法,通过实例展示了如何找到二进制数中1的位置。适用于初学者理解和掌握位操作的基础知识。
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