记录一下mpl学习结果:
[quote]1-1.
Turn vector_c<int,1,2,3> into a type sequence with elements (2,3,4) using transform.
[/quote]
对vector做一个加1就可以了
[quote]1-2.
Turn vector_c<int,1,2,3> into a type sequence with elements (1,4,9) using transform.
[/quote]
对两个AAA相乘
[quote]1-5.
There's still a problem with the dimensional analysis code in section 1.1. Hint: What happens when you do:
f = f + m * a;
Repair this example using techniques shown in this chapter.[/quote]
加法操作支持两种类型,然后确保类型是一致的就可以了
[quote]1-1.
Turn vector_c<int,1,2,3> into a type sequence with elements (2,3,4) using transform.
[/quote]
对vector做一个加1就可以了
typedef mpl::vector_c<int,1,2,3> AAA;
typedef mpl::vector_c<int,2,3,4> CCC;
typedef mpl::transform<AAA,mpl::plus<_1, mpl::int_<1> > >::type BBB;
BOOST_STATIC_ASSERT((
mpl::equal<BBB,CCC>::type::value
));
[quote]1-2.
Turn vector_c<int,1,2,3> into a type sequence with elements (1,4,9) using transform.
[/quote]
对两个AAA相乘
typedef mpl::vector_c<int,1,4,9> DDD;
typedef mpl::transform<AAA,AAA, mpl::multiplies<_1,_2> >::type EEE;
BOOST_STATIC_ASSERT((
mpl::equal<DDD,EEE>::type::value
));[quote]1-5.
There's still a problem with the dimensional analysis code in section 1.1. Hint: What happens when you do:
f = f + m * a;
Repair this example using techniques shown in this chapter.[/quote]
加法操作支持两种类型,然后确保类型是一致的就可以了
template <class T, class D1, class D2>
quantity<T,D1>
operator+(quantity<T,D1> x, quantity<T,D2> y)
{
BOOST_STATIC_ASSERT((
mpl::equal<D1,D2>::type::value
));
return quantity<T,D1>(x.value() + y.value());
}
本文通过实例演示了如何使用MPL库进行元编程操作,包括对整数序列进行转换及算术运算,并展示了如何确保类型一致性。
190

被折叠的 条评论
为什么被折叠?



