ORA-01555处理

最新推荐文章于 2025-06-25 23:35:01 发布

原创最新推荐文章于 2025-06-25 23:35:01 发布 · 154 阅读

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本文介绍了一种解决Oracle数据库中大型表导出时出现1555错误的方法。通过复杂的SQL语句分段处理大表数据，避免了单一导出操作导致的问题。此方法利用了窗口函数来确定每段的开始和结束位置。

有时表太大，导出时出现1555错误，可以采用分段方式处理。
以下原理也不是很清楚，先记录一下，再研究。
select dbms_rowid.rowid_create(1, oid1, fid1, bid1, 0) rowid1,
dbms_rowid.rowid_create(1, oid2, fid2, bid2, 9999) rowid2
from (select a.*, rownum rn
from (select chunk_no,
min(oid1) oid1,
max(oid2) oid2,
min(fid1) fid1,
max(fid2) fid2,
min(bid1) bid1,
max(bid2) bid2
from (select chunk_no,
FIRST_VALUE(data_object_id) OVER(PARTITION BY chunk_no ORDER BY data_object_id, relative_fno, block_id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) oid1,
LAST_VALUE(data_object_id) OVER(PARTITION BY chunk_no ORDER BY data_object_id, relative_fno, block_id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) oid2,
FIRST_VALUE(relative_fno) OVER(PARTITION BY chunk_no ORDER BY data_object_id, relative_fno, block_id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) fid1,
LAST_VALUE(relative_fno) OVER(PARTITION BY chunk_no ORDER BY data_object_id, relative_fno, block_id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) fid2,
FIRST_VALUE(block_id) OVER(PARTITION BY chunk_no ORDER BY data_object_id, relative_fno, block_id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) bid1,
LAST_VALUE(block_id + blocks - 1) OVER(PARTITION BY chunk_no ORDER BY data_object_id, relative_fno, block_id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) bid2
from (select data_object_id,
relative_fno,
block_id,
blocks,
ceil(sum2 / chunk_size) chunk_no
from (select /*+ rule */ b.data_object_id,
a.relative_fno,
a.block_id,
a.blocks,
sum(a.blocks) over(order by b.data_object_id, a.relative_fno, a.block_id) sum2,
ceil(sum(a.blocks)
over() / &trunks) chunk_size
from dba_extents a, dba_objects b
where a.owner = b.owner
and a.segment_name = b.object_name
and nvl(a.partition_name, '-1') =
nvl(b.subobject_name, '-1')
and b.data_object_id is not null
and a.owner = upper('&owner')
and a.segment_name = upper('&table_name'))))
group by chunk_no
order by chunk_no) a);