Sqrt(x)

Implement int sqrt(int x).

Compute and return the square root of x.

 

public class Solution {
    public int mySqrt(int x) {
        if (x == 1) {
        	return 1;
        }
        long i = 0;
        long j = x / 2 + 1;
        while (i <= j) {
            long mid = (i + j) / 2;
            long sq = mid * mid;
            if (sq == x) {
            	return (int) mid;
            } else if (sq < x) {
            	i = mid + 1;
            } else {
            	j = mid - 1;
            }
        }
        return (int)j;
    }
}