Problem Statement
Fox Ciel is playing a board game with her friend Squirrel Liss. The game is played on an infinite strip of paper. The strip of paper is divided into consecutive cells. Each cell has an integer coordinate. Formally, for
each integer i, the left neighbor of cell i is cell (i-1) and the right neighbor of cell i is cell (i+1).
Each of the players has a single token called the fencer. At the beginning of the game, Ciel's fencer is in cell 0 and Liss's fencer is in cell d. Each of the fencers has a limit: its maximum move length. For Ciel's fencer the maximum move length is mov1 and
for Liss's fencer it is mov2.
The players take alternating turns. Ciel goes first. In each turn the current player moves her fencer. The distance between the original cell and the destination cell must be at most equal to the fencer's maximum move length. (It is also allowed to leave the
fencer in the same cell.) If the current player moves her fencer into the cell with the other fencer, the current player's fencer scores a hit and wins the game.
You are given the ints mov1, mov2, and d. Return "Ciel" (quotes for clarity) if Fox Ciel has a winning strategy, "Liss" if Squirrel Liss has a winning strategy, and "Draw" otherwise.
Definition
Class: FoxAndFencingEasy
Method: WhoCanWin
Parameters: int, int, int
Returns: string
Method signature: string WhoCanWin(int mov1, int mov2, int d)
(be sure your method is public)
Constraints
- mov1 will be between 1 and 100,000,000, inclusive.
- mov2 will be between 1 and 100,000,000, inclusive.
- d will be between 1 and 100,000,000, inclusive.
Examples
0)
1
58
1
Returns: "Ciel"
Ciel can win in her first turn by moving her fencer one cell to the right.
1)
100
100
100000000
Returns: "Draw"
Liss can avoid getting hit forever by repeating Ciel's moves. For example, whenever Ciel moves her fencer 47 cells to the right, Liss also moves her fencer 47 cells to the right. Ciel has a similar strategy: in her first turn she can move her fencer arbitrarily
and in each of the following turns she will repeat Liss's previous move. Therefore the game ends in a draw.
2)
100
150
100000000
Returns: "Draw"
3)
100
250
100000000
Returns: "Liss"
This problem statement is the exclusive and proprietary property of TopCoder, Inc. Any unauthorized use or reproduction of this information without the prior written consent of TopCoder, Inc. is strictly prohibited. (c)2003, TopCoder, Inc. All rights reserved.
至少得大于两倍才可以安全的追到另一个人
class FoxAndFencingEasy {
public:
string WhoCanWin(int mov1, int mov2, int d)
{
string Ciel("Ciel"),Liss("Liss"),Draw("Draw");
if(mov1>=d) return Ciel;
else if(mov1>2*mov2) return Ciel;
else if(mov2>2*mov1) return Liss;
else return Draw;
}
};
本文介绍了一款在无限延伸的赛道上进行的两人对战游戏。游戏中的两名玩家分别控制着能够移动不同距离的棋子,目标是在对方移动范围内击中对方棋子以赢得比赛。文章探讨了不同移动范围下的游戏结局,并提供了实现这一策略的代码。
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