zoj 3190 Resource Archiver 【构造最短不含病毒串的串】

Run ID Submit Time Judge Status Problem ID Language Run Time(ms) Run Memory(KB) User Name
2897194 2012-05-19 09:54:06 Accepted 3190 C++ 110 3524 zz_1215

ac自动机,我的方法是先用bfs构造最短路,然后在最短路的图上进行记忆化搜索,代码长的一b,敲完样例都没通过,- - 然后改了半天好不容易通过样例,一交。。。1y啊我擦!!奇迹了...

110ms...

#include<iostream>
#include<vector>
#include<algorithm>
#include<cstdio>
#include<queue>
#include<stack>
#include<string>
#include<map>
#include<set>
#include<cmath>
#include<cassert>
#include<cstring>
#include<iomanip>
using namespace std;

#ifdef _WIN32
#define i64 __int64
#define out64 "%I64d\n"
#define in64 "%I64d"
#else
#define i64 long long
#define out64 "%lld\n"
#define in64 "%lld"
#endif

#define FOR(i,a,b)      for( int i = (a) ; i <= (b) ; i ++)
#define FF(i,a)         for( int i = 0 ; i < (a) ; i ++)
#define FFD(i,a)        for( int i = (a)-1 ; i >= 0 ; i --)
#define S64(a)          scanf(in64,&a)
#define SS(a)           scanf("%d",&a)
#define LL(a)           ((a)<<1)
#define RR(a)           (((a)<<1)+1)
#define pb              push_back
#define CL(Q)           while(!Q.empty())Q.pop()
#define MM(name,what)   memset(name,what,sizeof(name))
#define read            freopen("in.txt","r",stdin)
#define write           freopen("out.txt","w",stdout)

const int inf = 0x3f3f3f3f;
const i64 inf64 = 0x3f3f3f3f3f3f3f3fLL;
const double oo = 10e9;
const double eps = 1e-10;
const double pi = acos(-1.0);
const int maxz = 100000;
const int maxn = 1<<10;
const int maxp = 111;
const int head = 0;

int zx[maxz][2];
int fail[maxz];
int id[maxz];
int der[maxz];
bool yes[maxz];
bool no[maxz];
bool vis[maxz];
int dis[maxz];
int way[maxp][maxp];
int dp[maxp][maxn+1];
int has[maxp];
int hash[maxp];
bool inq[maxz];
int use,df;
int n,m;
vector<int>v;

int get()
{
    use++;
    zx[use][0] = zx[use][1] = -1;
    id[use] = -2;
    fail[use] = 0;
    yes[use] = false;
    no[use] = false;
    return use;
}

void insert(int ids,string & p)
{
    int now = head;
    int c;
    for(int i=0;i<p.length();i++)
    {
        c = p[i]-'0';
        if(zx[now][c] != -1)
        {
            now = zx[now][c];
        }
        else
        {
            zx[now][c] = get();
            now = zx[now][c];
        }
    }
    id[now] = ids;
    return ;
}

void ac()
{
    queue<int>q;
    CL(q);
    q.push(head);
    int now,to,temp;
    while(!q.empty())
    {
        now = q.front();
        q.pop();
        for(int i=0;i<2;i++)
        {
            if(zx[now][i] != -1)
            {
                to = zx[now][i];
                q.push(to);
                temp = now;
                while(temp)
                {
                    temp = fail[temp];
                    if(zx[temp][i]!= -1)
                    {
                        temp = zx[temp][i];
                        break;
                    }
                }
                fail[to] = temp;
            }
        }
    }
    return ;
}

bool findno(int now)
{
    if(vis[now]) return no[now];
    vis[now] = true;
    if(id[now]==-1) return no[now] = true;
    return no[now] = findno(fail[now]);
}

bool findyes(int now)
{
    if(vis[now]) return yes[now];
    vis[now] = true;
    if(no[now]) return yes[now] = false;
    if(id[now]>=0) return yes[now] = true;
    return yes[now] = findyes(fail[now]);
}

void find(int snow)
{
    queue<int>q;
    CL(q);
    MM(inq,false);
    for(int i=0;i<=use;i++)
    {
        dis[i] = inf;
    }
    q.push(snow);
    inq[snow] = true;
    dis[snow] = 0;
    int now,to,temp;
    while(!q.empty())
    {
        now = q.front();
        q.pop();
        for(int i=0;i<2;i++)
        {
            if(zx[now][i]!=-1)
            {
                to = zx[now][i];
            }
            else
            {
                temp = now;
                while(temp)
                {
                    temp = fail[temp];
                    if(zx[temp][i]!=-1)
                    {
                        temp = zx[temp][i];
                        break;
                    }
                }
                zx[now][i] = temp;
                to = temp;
            }
            if(!no[to])
            {
                if(dis[now] + 1 < dis[to])
                {
                    dis[to] = dis[now] + 1;
                    if(!inq[to])
                    {
                        q.push(to);
                        inq[to] = true;
                    }
                }
            }
        }
        inq[now] = false;
    }
    now = der[snow];
    for(int i=0;i<=use;i++)
    {
        if(der[i]!=-1)
        {
            to = der[i];
            way[now][to] = dis[i];
        }
    }
    return ;
}

void find2(int now)
{
    if(now)
    {
        if(id[now]>=0)
        {
            has[df] |= 1<<id[now];
        }
        find2(fail[now]);
    }
    return ;
}

struct sa
{
    int pos;
    int sf;
}sd;

bool hashset[maxp][maxn+1];

void ak()
{
    deque<sa>q;
    for(int i=0;i<=df;i++)
    {
        for(int j=0;j<(1<<n);j++)
        {
            dp[i][j] = inf;
            hashset[i][j] = false;
        }
    }

    q.clear();
    sd.pos = 0;
    sd.sf = 0;
    q.push_back(sd);
    dp[0][0] = 0;
    hashset[0][0] = true;
    sa now,to;
    int temp;
    int cost;
    while(!q.empty())
    {
        now = q.front();
        q.pop_front();
        for(int i=0;i<=df;i++)
        {
            if(i == now.pos) continue;
            temp = way[now.pos][i] + dp[now.pos][now.sf];
            to.pos = i;
            to.sf = now.sf | has[i];
            if(temp < dp[to.pos][to.sf])
            {
                dp[to.pos][to.sf] = temp;
                if(!hashset[to.pos][to.sf])
                {
                    hashset[to.pos][to.sf] = true;
                    if(!q.empty() && temp < dp[q.front().pos][q.front().sf] )
                    {
                        q.push_front(to);
                    }
                    else
                    {
                        q.push_back(to);
                    }
                }
            }
        }
        hashset[now.pos][now.sf] = false;
    }
    return ;
}

int start()
{
    for(int i=0;i<maxp;i++)
    {
        has[i] = 0;
    }
    df = 1;
    MM(vis,false);
    MM(has,0);
    MM(der,-1);
    ac();
    vis[0] = true;
    no[0] = false;
    for(int i=0;i<=use;i++) findno(i);
    MM(vis,false);
    vis[0] = true;
    yes[0] = false;
    der[0] = 0;
    v.clear();
    v.push_back(0);
    for(int i=0;i<=use;i++) if(findyes(i))
    {
        find2(i);
        der[i] = df++;
        v.push_back(i);
    }
    for(int i=0;i<maxp;i++)
    {
        for(int j=0;j<maxp;j++)
        {
            way[i][j] = inf;
        }
    }
    for(int i=0;i<maxp;i++)
    {
        way[i][i] =  0;
    }
    df--;
    for(int i=0;i<v.size();i++)
    {
        find(v[i]);
    }

    ak();

    int ans = inf;
    for(int i=0;i<=df;i++)
    {
        ans = min(ans,dp[i][(1<<n)-1]);
    }

    return ans;
}

int main()
{
    while(cin>>n>>m)
    {
        if(!n && !m) break;
        string s;
        use = -1;
        get();
        for(int i=0;i<n;i++)
        {
            cin>>s;
            insert(i,s);
        }

        for(int i=1;i<=m;i++)
        {
            cin>>s;
            insert(-1,s);
        }
        cout<<start()<<endl;
    }
    return 0;
}





评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值